y to the six is common, so it becomes y^3(y^3 - 125). Then we use difference of cubes ((a-b)(a^2 - 2ab + b^2)), so it becomes y^3(y-5)(y^2 + 5y + 25). Since we cannot factor out that last quadratic part, this concludes the factoring process and we end up with that last line as our answer.
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it is x to the sixth power
(x - 2)(x + 2)(x2 - 2x + 4)(x2 + 2x + 4)
simplified it would equal: 24x to the third power - x to the second power - x to the sixth power - 34
One minus a sixth is five sixths.
x^7-x^6 is already in simplest form.