y to the six is common, so it becomes y^3(y^3 - 125). Then we use difference of cubes ((a-b)(a^2 - 2ab + b^2)), so it becomes y^3(y-5)(y^2 + 5y + 25). Since we cannot factor out that last quadratic part, this concludes the factoring process and we end up with that last line as our answer.
it is x to the sixth power
(x - 2)(x + 2)(x2 - 2x + 4)(x2 + 2x + 4)
simplified it would equal: 24x to the third power - x to the second power - x to the sixth power - 34
One minus a sixth is five sixths.
x^7-x^6 is already in simplest form.
91,000,000
it is x to the sixth power
(x - 2)(x + 2)(x2 - 2x + 4)(x2 + 2x + 4)
simplified it would equal: 24x to the third power - x to the second power - x to the sixth power - 34
One minus a sixth is five sixths.
x^7-x^6 is already in simplest form.
Tenth to the ninth minus ten to the sixth = ten to the third.
3^6 = 729
There is no repeated factor. 10-6 = 1/1000000 or a millionth.
Twelve eighths minus one sixth is one and one third.
Three quarters
No, any number raised to an even power (6, in this case) is positive or zero. So, the sixth root of minus one can only be a complex number.