3x2 - 8x = x(3x - 8)
Factorise it: (x + 5)(3x - 8)
10
5*2-3x-1 = 0 10-3x-1 = 0 -3x = 1-10 -3x = -9 x = 3
I think you mean (3x ± 1)^2 = (3x+1)(3x-1)?
3x2 - 8x = x(3x - 8)
2(2x-11)(3x+5)
It is: 3y(2y-3x) when factored
Factorise it: (x + 5)(3x - 8)
12x2 - 7x + 1 = 12x2 - 4x - 3x + 1 = 4x(3x - 1) - 1(3x - 1) = (3x - 1)(4x - 1)
(x-1)(2x+5)
12x2 + 7x + 1 = 12x2 + 3x + 4x + 1 = 3x*(4x + 1) + 1*(4x + 1) = (4x + 1)*(3x + 1)
10
6x^3 + 3x = 3x(2x^2 + 1)
5*2-3x-1 = 0 10-3x-1 = 0 -3x = 1-10 -3x = -9 x = 3
That factors to 3x(3x - 1)
(x-3)(3x+1)