To factorise the expression (3X - 1), we look for common factors. In this case, there are no common factors between the two terms. Therefore, the expression is already in its simplest form and cannot be further factorised. The expression can be expressed as (1(3X - 1)), but that doesn't change its form.
3x2 - 8x = x(3x - 8)
Factorise it: (x + 5)(3x - 8)
10
5*2-3x-1 = 0 10-3x-1 = 0 -3x = 1-10 -3x = -9 x = 3
I think you mean (3x ± 1)^2 = (3x+1)(3x-1)?
3x2 - 8x = x(3x - 8)
2(2x-11)(3x+5)
It is: 3y(2y-3x) when factored
Factorise it: (x + 5)(3x - 8)
12x2 - 7x + 1 = 12x2 - 4x - 3x + 1 = 4x(3x - 1) - 1(3x - 1) = (3x - 1)(4x - 1)
(x-1)(2x+5)
12x2 + 7x + 1 = 12x2 + 3x + 4x + 1 = 3x*(4x + 1) + 1*(4x + 1) = (4x + 1)*(3x + 1)
10
5*2-3x-1 = 0 10-3x-1 = 0 -3x = 1-10 -3x = -9 x = 3
6x^3 + 3x = 3x(2x^2 + 1)
That factors to 3x(3x - 1)
(x-3)(3x+1)