Assuming you mean positive whole numbers, then all numbers greater than 1 can be factorised using prime numbers only. Some of the numbers are prime themselves, eg 2, 3, 5, 7 and so factorise into themselves; others are composite and so factorise into the product of 2 primes, eg 8 = 2 x 2 x 2, 12 = 2 x 2 x 3
a2+16 cannot be factored. There are no two numbers whose product is 16 and whose sum is 0.
a²-a = a(a-1)
Placing a question mark at the end of a list of expressions or numbers does not make it a sensible question. What do you want? To evaluate it (impossible), factorise it, something else?
you do (245x)
To factorise is to find the numbers that divide into the original number by only using prime numbers. For example factorise 20 = 2 times 2 times 5
Up till now you can't but hopefully will be able to do so soon.
Assuming you mean positive whole numbers, then all numbers greater than 1 can be factorised using prime numbers only. Some of the numbers are prime themselves, eg 2, 3, 5, 7 and so factorise into themselves; others are composite and so factorise into the product of 2 primes, eg 8 = 2 x 2 x 2, 12 = 2 x 2 x 3
Factorise fully is when brackets are involved in the equation
a2+16 cannot be factored. There are no two numbers whose product is 16 and whose sum is 0.
a²-a = a(a-1)
Two numbers differing by 9 whose product is 112? 7 & 16 (x + 7)(x - 16)
Placing a question mark at the end of a list of expressions or numbers does not make it a sensible question. What do you want? To evaluate it (impossible), factorise it, something else?
to put into brackets
you do (245x)
x2-2x+3 does not factor over the field of real numbers. Over the complex numbers, it factors as (x - 1 +is)(x -1 -is) where s is the square root of 2.
The answer will depend on where the brackets are. In general the solution would be to expand all the brackets, combine like terms and then factorise.