x2-2x+3 does not factor over the field of real numbers.
Over the complex numbers, it factors as (x - 1 +is)(x -1 -is) where s is the square root of 2.
(x - 3)(2x - 7)
You cannot since the expression does not have rational roots.
The answer is (2x^2+3)(4x+1)
(2x-3)(x-1)
2x2+5x+3 = (2x+3)(x+1) when factored
(x - 3)(2x - 7)
17
2x + 6 = 2(x+3)
It is 2(2x+3) when factorised
(2x+3)(x+3)
(5x + 2)(x + 3)
2x(y - 3) + 7(y - 3) = (2x + 7)(y - 3)
You cannot since the expression does not have rational roots.
(2x+3)(x+3)
(2x - 3)(2x - 3)
(2x+3)(2x+4)
The answer is (2x^2+3)(4x+1)