There really isn't much to simplify there. You might consider it as the difference of two squares - the square of x1/4 and the square of 11/4 (or simply the square of 1), but factoring that will get you an expression that is more complicated, not simpler, than the original.
1/2
1 minus a half is a half.
x4 - x3 - x - 1 rewriting: = x4 - 1 - x3 - x factorising pair of terms: =(x2 + 1)*(x2 - 1) - x*(x2 + 1) = (x2 + 1)*(x2 - 1 - x) or (x2 + 1)*(x2 - x - 1) which cannot be factorised further.
I'll say no. Let's look at it: Try to make the first part rearrange to look like: 2 / sqrt(X) = 2 / [x^(1/2)] = 2 * x^(-1/2)Half X to the power minus half could mean(Half of X) to the power (minus half) = (X/2)^(-1/2) = [(1/2)^(-1/2)] * [(X)^(-1/2)] = [(2)^(1/2)] / [(X)^(1/2)] = sqrt(2) / sqrt(X), which is not the same.If you mean Half of [X to the power (minus half)] = (1/2) * (X)^(-1/2) = (1/2) / (X)^(1/2) =1 / [2*sqrt(X)], which is not the same either.
2y2(3y - 1)
1/2
1 minus a half is a half.
x4 - x3 - x - 1 rewriting: = x4 - 1 - x3 - x factorising pair of terms: =(x2 + 1)*(x2 - 1) - x*(x2 + 1) = (x2 + 1)*(x2 - 1 - x) or (x2 + 1)*(x2 - x - 1) which cannot be factorised further.
5x2 + 9x + 13 has no real factors.
I'll say no. Let's look at it: Try to make the first part rearrange to look like: 2 / sqrt(X) = 2 / [x^(1/2)] = 2 * x^(-1/2)Half X to the power minus half could mean(Half of X) to the power (minus half) = (X/2)^(-1/2) = [(1/2)^(-1/2)] * [(X)^(-1/2)] = [(2)^(1/2)] / [(X)^(1/2)] = sqrt(2) / sqrt(X), which is not the same.If you mean Half of [X to the power (minus half)] = (1/2) * (X)^(-1/2) = (1/2) / (X)^(1/2) =1 / [2*sqrt(X)], which is not the same either.
8x2 - 10x - 3 = (2x - 3)(4x + 1)
2y2(3y - 1)
7
1
1 minus 1/2 minus 1/3 is equal to 0.166667
1/4 minus 1/2 is -1/4.
It is: 1.5 minus 1.25 = 0.25 or 1/4