Yes: product of a & b = LCM x HCF so b = (LCM x HCF)/a
As a product of its prime factors: 2*5*7 = 70 Note that at least two or more numbers are needed to find their HCF
Yes.
The LCM is the product of the two numbers divided by their HCF. With 12 and 13, the HCF is 1. Therefore, the LCM will equal the product. With 12 and 14, the HCF is 2. Therefore, the LCM will be half of the product.
there cannot be any nos like that.. product of 2 odd nos is odd.. sum of two even nos is even.. that multiplied by six is even too.. subtracting 2 from that also gives an even no.. let x and y be the odd integers. according to the given question xy=6(x+y)-2..here we r actually equatin an odd no and an even no.. which is wrong.. so there cant be any two consecutive odd nos that fit in the question
The GCF of two prime numbers is 1.
At least 2 or more numbers are needed to find their hcf but 66 as a product of its prime factors is: 2*3*11 = 66
To find the LCM, you multiply the numbers together and then divide by the HCF. In this case, we don't know the numbers, but we have the HCF (13) and we have the product of the numbers (1690). Thus all you do is divide 1690 by 13 to get: 1690/13 = 130 And thus the LCM of two numbers whose hcf is 13 and product is 1690 is 130.
Yes: product of a & b = LCM x HCF so b = (LCM x HCF)/a
As a product of its prime factors: 2*5*7 = 70 Note that at least two or more numbers are needed to find their HCF
Yes.
Any two of the same number. The GCF and LCM of 10 and 10 is 10.
The LCM is the product of the two numbers divided by their HCF. With 12 and 13, the HCF is 1. Therefore, the LCM will equal the product. With 12 and 14, the HCF is 2. Therefore, the LCM will be half of the product.
Factors: 15 = 3 x 5, 18 = 2 x 3 x 3. The LCM of two numbers = their product divided by their HCF. In this instance the product is 270 and the HCF is 3 so the LCM is 90.
2 and 3.
The answer is as follows:The prime factorisation of the two number is:18 = 2*3*324 = 2*2*2*3The HCF is the product every number which appears in both lists (repeated appearances mean repeated inclusion in HCF):HCF = 2*3 = 6
Since the product of two numbers is equal to the product of their GCF and LCM, the GCF of two numbers is equal to their product divided by their LCM and their LCM is equal to their product divided by their GCF.