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If LCM and HCF is known of 2 number along with 1 number can you find second number?
Yes: product of a & b = LCM x HCF so b = (LCM x HCF)/a
HCF of 70 by prime factorization method?
As a product of its prime factors: 2*5*7 = 70 Note that at least two or more numbers are needed to find their HCF
Is the product of the 2 original numbers equal to the product of the HCF and the LCM?
Yes.
Why is the LCM of 12 and 13 the same as there product but the LCM of 12 and 14 is not the same as there product?
The LCM is the product of the two numbers divided by their HCF. With 12 and 13, the HCF is 1. Therefore, the LCM will equal the product. With 12 and 14, the HCF is 2. Therefore, the LCM will be half of the product.
The product of two consecutive odd integers is 2 less than six times their sum can you find the two integers?
there cannot be any nos like that.. product of 2 odd nos is odd.. sum of two even nos is even.. that multiplied by six is even too.. subtracting 2 from that also gives an even no.. let x and y be the odd integers. according to the given question xy=6(x+y)-2..here we r actually equatin an odd no and an even no.. which is wrong.. so there cant be any two consecutive odd nos that fit in the question
What is the HCF of 2 prime nos?
The GCF of two prime numbers is 1.
What ius the hcf of 66 prime?
At least 2 or more numbers are needed to find their hcf but 66 as a product of its prime factors is: 2*3*11 = 66
If 13 is HCF of 2 number whose product is 1690 find the LCM?
To find the LCM, you multiply the numbers together and then divide by the HCF. In this case, we don't know the numbers, but we have the HCF (13) and we have the product of the numbers (1690). Thus all you do is divide 1690 by 13 to get: 1690/13 = 130 And thus the LCM of two numbers whose hcf is 13 and product is 1690 is 130.
If LCM and HCF is known of 2 number along with 1 number can you find second number?
Yes: product of a & b = LCM x HCF so b = (LCM x HCF)/a
HCF of 70 by prime factorization method?
As a product of its prime factors: 2*5*7 = 70 Note that at least two or more numbers are needed to find their HCF
Is the product of the 2 original numbers equal to the product of the HCF and the LCM?
Yes.
Which 2 nos have same LCM and HCF?
Any two of the same number. The GCF and LCM of 10 and 10 is 10.
Why is the LCM of 12 and 13 the same as there product but the LCM of 12 and 14 is not the same as there product?
The LCM is the product of the two numbers divided by their HCF. With 12 and 13, the HCF is 1. Therefore, the LCM will equal the product. With 12 and 14, the HCF is 2. Therefore, the LCM will be half of the product.
How do you find the LCM of 15 and 18?
Factors: 15 = 3 x 5, 18 = 2 x 3 x 3. The LCM of two numbers = their product divided by their HCF. In this instance the product is 270 and the HCF is 3 so the LCM is 90.
What two nos have a sum of 5 and product of 6?
2 and 3.
What is the HCF of 120 and 180?
The Highest Common Factor (HCF) of 120 and 180 is the largest number that divides both 120 and 180 without leaving a remainder. To find the HCF, we need to factorize both numbers into their prime factors. The prime factorization of 120 is 2^3 * 3 * 5, and the prime factorization of 180 is 2^2 * 3^2 * 5. To find the HCF, we take the product of the common prime factors with the lowest exponent, which is 2^2 * 3 = 12. Therefore, the HCF of 120 and 180 is 12.
Find the Highest common factor (HCF) of 18 and 24. Show working.?
The answer is as follows:The prime factorisation of the two number is:18 = 2*3*324 = 2*2*2*3The HCF is the product every number which appears in both lists (repeated appearances mean repeated inclusion in HCF):HCF = 2*3 = 6
