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If LCM and HCF is known of 2 number along with 1 number can you find second number?
Yes: product of a & b = LCM x HCF so b = (LCM x HCF)/a
HCF of 70 by prime factorization method?
As a product of its prime factors: 2*5*7 = 70 Note that at least two or more numbers are needed to find their HCF
Is the product of the 2 original numbers equal to the product of the HCF and the LCM?
Yes.
Why is the LCM of 12 and 13 the same as there product but the LCM of 12 and 14 is not the same as there product?
The LCM is the product of the two numbers divided by their HCF. With 12 and 13, the HCF is 1. Therefore, the LCM will equal the product. With 12 and 14, the HCF is 2. Therefore, the LCM will be half of the product.
The product of two consecutive odd integers is 2 less than six times their sum can you find the two integers?
there cannot be any nos like that.. product of 2 odd nos is odd.. sum of two even nos is even.. that multiplied by six is even too.. subtracting 2 from that also gives an even no.. let x and y be the odd integers. according to the given question xy=6(x+y)-2..here we r actually equatin an odd no and an even no.. which is wrong.. so there cant be any two consecutive odd nos that fit in the question
