there cannot be any nos like that.. product of 2 odd nos is odd.. sum of two even nos is even.. that multiplied by six is even too.. subtracting 2 from that also gives an even no.. let x and y be the odd integers. according to the given question xy=6(x+y)-2..here we r actually equatin an odd no and an even no.. which is wrong.. so there cant be any two consecutive odd nos that fit in the question
One possible answer is -4 and -3.
The 3 consecutive odd positive integers are 7, 9 and 11.
They are -10 and -9.
Two negative consecutive odd integers that have a product of 63 are -7 and -9. -7 is larger than -9. -7 is the answer.
Let the two consecutive negative odd integers be ( x ) and ( x + 2 ). The equation for their product is ( x(x + 2) = 399 ). This simplifies to ( x^2 + 2x - 399 = 0 ). Solving this quadratic equation, we find that the integers are ( -19 ) and ( -17 ), since ( -19 \times -17 = 399 ).
9240 is the product of the three consecutive integers 20, 21, and 22.
One possible answer is -4 and -3.
The 3 consecutive odd positive integers are 7, 9 and 11.
Yes, the integers are 12 and 13.
There are no two consecutive even integers, consecutive odd integers, or consecutive integers that satisfy that relationship.
They are are 7 and 8.
They are -10 and -9.
11 and 13
13 & 15
-10, -9 and -8
Two negative consecutive odd integers that have a product of 63 are -7 and -9. -7 is larger than -9. -7 is the answer.
The numbers are 11, 13, 15 and 17.