Put 0 in for x and solve for y to find the y intercept. Put 0 in for y and solve for x to find the x intercept.
-4(0)+3y=10
y=10/3
y intercept is (0,10/3)
-4x+3(0)=10
x=-10/4
x intercept is (-10/4,0)
The y intercept is 10 and the x intercept is -4
x-intercept | -10 y-intercept | 4 slope | 2/5 = 0.4
The x intercepts are when y=0. Substitute the zero in for all y and then solve. Use quadratic formula and reduce. I got (-1+/- sqrt 10)3 about .72075922 and -1.387425887
To find x, sub 0 in for y. To find y, sub 0 in for x.y= -10, x= 4
-4 plus 10 equals 6.
The y intercept is 10 and the x intercept is -4
y-intercept would be 10 and x intercept would be -6
x-intercept | -10 y-intercept | 4 slope | 2/5 = 0.4
x^2+8x=20 x^2+8x-20=0 (x+10)(x-2)=0 x=-10 and x=2 are the roots (intercepts) (-10,0) and (2,0) are the x-intercepts.
The x intercepts are when y=0. Substitute the zero in for all y and then solve. Use quadratic formula and reduce. I got (-1+/- sqrt 10)3 about .72075922 and -1.387425887
To find x, sub 0 in for y. To find y, sub 0 in for x.y= -10, x= 4
y = 5x2 - 5x + 1 (replace y with 0 to find the x-intercepts) 0 = 5x2 - 5x + 1 (use the quadratic formula, x = [-b ± √(b - 4ac)]/2a) x = [-(-5) ± √[(-5)2 - 4(5)(1)]]/2(5) x = [5 ± √(25 - 20)]/10 x = (5 ± √5)/10 x ≈ (5 ± 2.25)/10 x ≈ (5 + 2.25)/10 or x ≈ (5 - 2.25)/10 x ≈ 7.25/10 = 0.725 or x ≈ 2.75/10 = 0.275 So the x-intercepts are approximately 0.275 and 0.725.
By completing the square y = (x+3)2+1 Axis of symmetry and vertex: x = -3 and (-3, 1) Note that the parabola has no x intercepts because the discriminant is less than zero
-4 plus 10 equals 6.
If x equals 10 and y equals 10, then 9x plus 8y equals 170.
-5
x=10