To find x, sub 0 in for y. To find y, sub 0 in for x.
y= -10, x= 4
for the equation:5x + 10y = 20, the two intercepts are:x = 0 , y = 2 or (0,2)y = 0 , x = 4 or (4,0)The graph is a straight line passing through the two intercepts (0,2) and (4,0)
y = 0 gives 0 = - x - 20 so that x = -20 So the intercept is (-20, 0)
You should be able to look at that and realize . . .--> y = 4--> The graph is a horizontal line.--> It doesn't cross the x-axis anywhere.--> 'y' is 4 at every point on the line, including the pointwhere it crosses the y-axis.
x-intercept | -10 y-intercept | 4 slope | 2/5 = 0.4
If you mean: 5x-2y = 20 then y = 2.5x-10 whereas the slope is 2.5 and the y intercept is -10 The x intercept will be at: (4, 0)
for the equation:5x + 10y = 20, the two intercepts are:x = 0 , y = 2 or (0,2)y = 0 , x = 4 or (4,0)The graph is a straight line passing through the two intercepts (0,2) and (4,0)
-16
y = 0 gives 0 = - x - 20 so that x = -20 So the intercept is (-20, 0)
-5
x^2+8x=20 x^2+8x-20=0 (x+10)(x-2)=0 x=-10 and x=2 are the roots (intercepts) (-10,0) and (2,0) are the x-intercepts.
-20
You should be able to look at that and realize . . .--> y = 4--> The graph is a horizontal line.--> It doesn't cross the x-axis anywhere.--> 'y' is 4 at every point on the line, including the pointwhere it crosses the y-axis.
x-intercept | -10 y-intercept | 4 slope | 2/5 = 0.4
-2x = 20 + 5y-2x - 20 = 5y-2/5x - 4 = yX Intercept = (-10,0) or -10Y Intercept = (0,-4) or -4
If you mean: 5x-2y = 20 then y = 2.5x-10 whereas the slope is 2.5 and the y intercept is -10 The x intercept will be at: (4, 0)
23
y = 2x2 - 3x - 20 ∴ y = 2x2 - 8x + 5x - 20 ∴ y = 2x(x - 4) + 5(x - 4) ∴ y = (2x + 5)(x - 4) The x intercepts occur when y = 0, which happens when either of the two factors on the left side of the equation equal zero. This means that they are at the points (-5/2, 0) and (4, 0).