y-intercept would be 10 and x intercept would be -6
The intercepts of 2x + 3y - 6z = 30 are(15, 0, 0), (0, 10, 0) and (0, 0 , -5).
(6, 0) and (0, 8)
(3,3)
4x + 3y = 6y 4x = 3y 4/3 x = y The slope is 4/3 and the y intercept is 0.
-x + 3y = 6 3y = x 6 y = x/3 + 2 So slope = 1/3 and intercept = 2
To find the x-intercept of the equation (2x + 3y = 30), set (y = 0): (2x = 30), giving (x = 15). For the y-intercept, set (x = 0): (3y = 30), resulting in (y = 10). Therefore, the x-intercept is (15) and the y-intercept is (10).
The intercepts of 2x + 3y - 6z = 30 are(15, 0, 0), (0, 10, 0) and (0, 0 , -5).
x: x = 15 y: y = 10 z: z = -5
To find the intercepts of the equation (2x + 3y - 6z = 30), we set two variables to zero at a time. For the x-intercept, set (y = 0) and (z = 0): (2x = 30) gives (x = 15). For the y-intercept, set (x = 0) and (z = 0): (3y = 30) gives (y = 10). For the z-intercept, set (x = 0) and (y = 0): (-6z = 30) gives (z = -5). Thus, the intercepts are ( (15, 0, 0) ), ( (0, 10, 0) ), and ( (0, 0, -5) ).
If the equation is 7x - 3y = 21 then (3, 0) and (0, -7).
The result will be a plane that intercepts the x-, y-, and z-axes at +9, +6, and +3, respectively.
The y-intercept is the place (or places) where x=0 . So if 'x' is 2y2+3y+1 , then all you have to do is find places where 2y2+3y+1 is zero, and those are your y-intercepts.