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-- Draw a line segment from one point to the other.

-- Construct the perpendicular bisector of the line segment..

-- Every point on the perpendicular bisector of the line segment

is equidistant from the two original points.

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Whereupon the first contributor observed:

Yes, that works, no matter how you set the compass, as long as it's more than 1/2 the distance

between the two points. Every setting of the compass will give you a pair of points that are

equal distances from the original two. As you find more and more of them ... with different

settings of the compass ... you'll see that all the equal-distance points you're finding all lie

on the same straight line. That line is the perpendicular bisector of the line between the two

original points, just as we described up above.

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Q: How do you find a point which is equidistant from two other points?
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How do you find the equidistant point for a straight line?

The equidistant point of a straight line is the middle. Measure the distance from one end to the other and half it.


How do you find a point which is equidistant from a given pair of points?

Bisect two arcs above and below the given points or line and the perpendicular of these arcs cuts through the midpoint.


How do you find the equal distance from each of your three points?

It is the circumcentre of the triangle formed by the three points. Draw the perpendicular bisectors of two of the lines joining the three points. They will meet at the point that is equidistant from the three points.


How do you find a point which is equidistant from other three points?

For three points, (x1,y1), (x2,y2) & (x3,y3), you can set up 3 distance equations with variables x, y & z: z^2 = (x-x1)^2 + (y-y1)^2 z^2 = (x-x2)^2 + (y-y2)^2 z^2 = (x-x3)^2 + (y-y3)^2 3 equations and 3 variables....Solve away! z is your distance. x & y are the coordinates of the equidistant point.


How do I find the y-intercept if the line passes through negative 2 and 3?

You can't. There are an infinite number of lines that pass through the point (-2, 3).They all have different y-intercepts and different slopes.In order to narrow it down to a single line, you have to give more information.One more point would do it.=======================================================Here's the minimum information needed to define a unique line:-- you name 2 points; I find slope, intercept, and all other points.-- you name one point and one intercept ... 'x' or 'y'; I find slope and all other points.-- you name x-intercept and y-intercept; I find slope and all other points.-- you name one point and the slope; I find intercept and all other points.-- you name one intercept and the slope; I find all other points.