-- Draw a line segment from one point to the other.
-- Construct the perpendicular bisector of the line segment..
-- Every point on the perpendicular bisector of the line segment
is equidistant from the two original points.
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Whereupon the first contributor observed:
Yes, that works, no matter how you set the compass, as long as it's more than 1/2 the distance
between the two points. Every setting of the compass will give you a pair of points that are
equal distances from the original two. As you find more and more of them ... with different
settings of the compass ... you'll see that all the equal-distance points you're finding all lie
on the same straight line. That line is the perpendicular bisector of the line between the two
original points, just as we described up above.
Chat with our AI personalities
The equidistant point of a straight line is the middle. Measure the distance from one end to the other and half it.
Bisect two arcs above and below the given points or line and the perpendicular of these arcs cuts through the midpoint.
It is the circumcentre of the triangle formed by the three points. Draw the perpendicular bisectors of two of the lines joining the three points. They will meet at the point that is equidistant from the three points.
For three points, (x1,y1), (x2,y2) & (x3,y3), you can set up 3 distance equations with variables x, y & z: z^2 = (x-x1)^2 + (y-y1)^2 z^2 = (x-x2)^2 + (y-y2)^2 z^2 = (x-x3)^2 + (y-y3)^2 3 equations and 3 variables....Solve away! z is your distance. x & y are the coordinates of the equidistant point.
You can't. There are an infinite number of lines that pass through the point (-2, 3).They all have different y-intercepts and different slopes.In order to narrow it down to a single line, you have to give more information.One more point would do it.=======================================================Here's the minimum information needed to define a unique line:-- you name 2 points; I find slope, intercept, and all other points.-- you name one point and one intercept ... 'x' or 'y'; I find slope and all other points.-- you name x-intercept and y-intercept; I find slope and all other points.-- you name one point and the slope; I find intercept and all other points.-- you name one intercept and the slope; I find all other points.