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Find the equation for the locus of points equidistant from x 3 x 7?
Guillermosmith20425
Assuming the question should have said x = 3 and x = 7, the answer is x= 5.
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∙ 9y ago
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How can you find equation of the line passing thruogh two points?
. the equation of a straight line can be found by using two points on a line . First find the gradient of the line using the gradient formula . now substitute the gradient into general form replacing "m" . use one of the points and substitute into equation to solve "c" example 1: find the equation of the line which passes through the points (1,3) and (2,5). step 1: find the gradient M=5-3/2-1=2 (/=divide) step 2: place m into the equation Y=2x+c step 3: substitute point into equation 3=2(1)+c step 4: solve C=1 equation is Y=2x+1 hope that helps :)
How do you find the equation of a parabola in standard form given 3 points?
I suggest that the simplest way is as follows:Assume the equation is of the form y = ax2 + bx + c.Substitute the coordinates of the three points to obtain three equations in a, b and c.Solve these three equations to find the values of a, b and c.
How can you find an equation line between two pair of points?
Assuming you want the equation of the straight line between the two points (x0, y0) and (x1, y1), the equation is: y - y0 = m(x - x0) where m is the gradient between the two points: m = (y1 - y0) ÷ (x1 - x0) Note: if the two x coordinates are equal, that is x0 = x1, then the equation of the line is x = x0.
One way to find the equation of a line is to look at some points on it and try to find the relationship between the coordinates?
Yes. You need only two points. If A (ax, ay) and B (bx, by) are two points on the line then the gradient (slope) of the line is m = (by - ay)/(bx - ax) provided bx ≠ ax. From this you can calculate m. Then the general slope-intercept form of the equation is y = mx + c Substitute the coordinates of A or B into this equation to find c. If bx = ax then the line is parallel to the y axis and its equation is x = ax. [There are other methods but they are similar to the above]
What is the equation of the line containing the points (0, 0), (-3, -9), and (9, 27)?
you should know this Find the difference of the y values over the difference in your x values to find the slope. Put it into the slope intercept form of the equation with one of the points substituted in and find the intercept. Rewrite the equation with the slope and the intercept. (-9-0)/(-3-0)=-9/-3=3 The slope. 27=3(9)+b 27=27+b 0=b Equation-> y=3x
How do you find equidistant points on a globe?
In spherical geometry we look at the globe as the sphere S^2. Any plane intersecting the sphere will create a great circle. Now if you take any point on the globe and reflect it across that plane, you have another point that is equidistant from the plane. The sets of all these points will be equidistant from the great circle.
How do you find a point equidistant from three other points?
To find a point equidistant from three other points, construct perpendicular bisectors for two of the segments formed from three points. Note: this will be the center of the circle that has all three points on it's circumference. Three points, not in a straight line, form three pairs of points with each pair defining a different line. Take any pair of points and draw the perpendicular bisector of the line joining them. Repeat for one of the other pairs. These two perpendicular bisectors will meet at the point which is equidistant from all three points - the circumcenter of the triangle formed by the three points.
How do you find the equal distance from each of your three points?
It is the circumcentre of the triangle formed by the three points. Draw the perpendicular bisectors of two of the lines joining the three points. They will meet at the point that is equidistant from the three points.
How do you find a point which is equidistant from a given pair of points?
Bisect two arcs above and below the given points or line and the perpendicular of these arcs cuts through the midpoint.
How do you find the equation of a tangent line?
In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.
Is it easier to solve an equation for y first before finding points?
It is always easier to use an equation to find points since all you would have to do is substitute values into the equation to find the final unknown value that will tell the point. To get the equation, however, you would usually need to have some points at the start to help derive the equation in the end.
Given two points A and B in the three dimensional space what is the set of points equidistant from A and B?
A plane is the set of all points in 3-D space equidistant from two points, A and B. If it will help to see it, the set of all points in a plane that are equidistant from points A and B in the plane will be a line. Extend that thinking off the plane and you'll have another plane perpendicular to the original plane, the one with A and B in it. And the question specified that A and B were in 3-D space. Another way to look at is to look at a line segment between A and B. Find the midpoint of that line segment, and then draw a plane perpendicular to the line segment, specifying that that plane also includes the midpoint of the line segment AB. Same thing. The set of all points that make up that plane will be equidistant from A and B. At the risk of running it into the ground, given a line segment AB, if the line segment is bisected by a plane perpendicular to the line segment, it (the plane) will contain the set of all points equidistant from A and B.
How do you find Slope intercept equation of given two points?
Use the equation; y=mx+b where m is the slope Use your 2 points as y and b (intercept)
What is the equation of the line that contains the points -32 and 5-5?
THE QUESTION IS ACTUALLY WORDED. FIND THE EQUATION OF THE LINE THAT CONTAINS THE POINTS P1(-7,-4) AND P2(2,-8). ALGEBRA
Find the equation of the line containing the two points shown?
what is the slope of the line containing points (5-,-2) and (-5,3)? 2
How do you find the equation of a circle?
A circle is the locus of all points equidistant from a fixed point on the plane. The fixed point is called the centre of the circle and the equal distance is called the radius of the circle. We can derive the equation of the circle from the distance formula. Let O be the centre of the circle and r be the radius of the circle. Here the centre = Origin = (0, 0) and the radius = r units. The distance r = sqrt ((x-0)2 + (y-0)2) r = sqrt (x2 + y2) Squaring both the sides, we get x2 + y2 = r2 This is the equation of the circle with centre as Origin. If the centre point is some (h, k), then use the distance formula to find the radius r. The distance r = sqrt ((x-h)2 + (y-k)2) Squaring both sides, we get (x-h)2 + (y-k)2 = r2. This is the equation of the circle with centre as the point (h, k).
Why do you need to find the equation of a line?
So that you can plot out the points of a straight line on graph paper.
