The set of points 26.5 units away from the point (2, 6) are those points that lie on the circle with centre (2, 6) and radius 26.5; this has equation:
(x - 2)² + (y - 6)² = 26.5²
The set of points 26.5 units away from the line y = 2 are those points which lie on the lines which are parallel to 26.5 and 2 units away, ie the lines y = 2 ± 26.5→y = -24.5 or y = 28.5
The points where these lines meet the circle are the required points.
By substituting the y values of the two lines into the equation for the circle and solving it will give you the required points.
That's HOW to find all the points.
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Solving the problem and finding the points:
→ x² - 4x + 4 + 30.5² - 26.5² = 0
→ x² - 4x + 232 = 0
→ x = 2(1 ± √-57)
As the square root is of a negative number the line does not meet the circle - it has no points in common
→ x² - 4x + 4 + 22.5² - 26.5² = 0
→ x² - 4x - 192 = 0
→ (x + 12)(x - 16) = 0
→ x = -12 or 16
→ points are (-12, 28.5) and (16, 28.5)
→ all the points that are 26.5 units away from the point (2, 6) and the line y = 2 are (-12, 28.5) and (16, 28.5).
To find the slope, you must have at least two points, not one. You cannot find the slope at one point, because coordinate points do not have slopes - lines have slopes.
-3 to 2 is +5 units so move another +5 units to +7 -4 to -1 is +3 units so move another +3 units to +2 So the other end point is (7,2)
Infinitely many. There are infinitely many points in the plane and although any pair of points define a line, no matter how many lines you are given, it is always possible to find a point that is not on any of them - that is, a point that is not collinear.
To find the inflection points on a graph, you need to take the second derivative. Then, set that equal to zero to find the x value(s) of the inflection point(s).
You can't. There are an infinite number of lines that pass through the point (-2, 3).They all have different y-intercepts and different slopes.In order to narrow it down to a single line, you have to give more information.One more point would do it.=======================================================Here's the minimum information needed to define a unique line:-- you name 2 points; I find slope, intercept, and all other points.-- you name one point and one intercept ... 'x' or 'y'; I find slope and all other points.-- you name x-intercept and y-intercept; I find slope and all other points.-- you name one point and the slope; I find intercept and all other points.-- you name one intercept and the slope; I find all other points.
Here's an example: In the coordinate plane, the point is translated to the point . Under the same translation, the points and are translated to and , respectively. What are the coordinates of and ? Any translation sends a point to a point . For the point in the problem, we have the following. So we have . Solving for and , we get and . So the translation is unit to the right and units up. See Figure 1. We can now find and . They come from the same translation: unit to the right and units up. The three points and their translations are shown in Figure 2.
The two points are (2, -3) and (-4, 5). To start at the origin, O, which is (0, 0). Then, to find any point, such as (p, q), you move p units to the right (to the left if p is negative) and then q units up (down if q is negative). So, the first point is 2 units to the righ and 3 down. The second is 4 to the left and 5 up.
To find the coordinates of points on the x-axis that are 5 units away from the point (6, -3), we can use the distance formula. The distance formula is: Distance = √((x2 - x1)^2 + (y2 - y1)^2) In this case, we know that x1 = 6, y1 = -3, and distance = 5. We also know that the points are on the x-axis, so the y-coordinate is 0. So we can plug these values into the distance formula and solve for x2: 5 = √((x2 - 6)^2 + (0 - (-3))^2) 5 = √(x2 - 6)^2 + 9 25 = (x2 - 6)^2 x2 = √25 + 6 = √16 + 6 = 4 + 6 = 10 Therefore, the coordinates of the point on the x-axis that is 5 units away from (6, -3) in the positive direction of x-axis are (10, 0) and the point on the x-axis that is 5 units away from (6, -3) in the negative direction of x-axis is (2,0).
To find the slope, you must have at least two points, not one. You cannot find the slope at one point, because coordinate points do not have slopes - lines have slopes.
The run, combined with the rise (the distance in units up) creates the slope of a line. In the slope 5/3 , 5 is the rise and 3 is the run, meaning that to find the next point on the line you would first move up five units, then go to the right 3 units.
The distance between the points of (4, 3) and (0, 3) is 4 units
The distance between the points of (4, 3) and (0, 3) is 4 units
since you know of one points and the halfway point between the other point. just multiply the halfway point by 2 and this is the total distance between the two points.
It will travel pi*R units along a cycloid.
The points are Dependent. Just pot the points and put two arrows at the end of the lines.
-3 to 2 is +5 units so move another +5 units to +7 -4 to -1 is +3 units so move another +3 units to +2 So the other end point is (7,2)
To find the slope (steepness, not height) of a line when given two points, do the following: Slope = (y2-y1)/(x2-x1), where (x1, y1) is one point, and (x2,y2) is the second point.