The distance between the points of (4, 3) and (0, 3) is 4 units
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I'm assuming that these are 3-D coordinates A(0,0,0) and B(3,4,5) The distance formula between two points in 3 dimensions is the following: D = SQR {(x1-x2)2 + (y1-y2)2 + (z1-z2)2} D = SQR {(0-3)2 + (0-4)2 + (0-5)2} D = SQR {9+16+25} = SQR {50} D is approx. = 7.07
Simply divide the difference in the y-coordinates, by the difference in the x-coordinates.
Passing through the points of -8-0 and 1-5 Difference between y coordinates of first and second points: =(-0) - (-5) = +5 Difference between x coordinates of first and second points: =(-8) - (1) = -9 So slope = 5/(-9) = -5/9
If you mean points of: (0, 3) and (8, -4) then it works out as -7/8
the numbers between 0 and 1 is 0.1,0.2,0.3,0.4,0.5,0.6,0.7,0.8,0.9,0.10.