The distance between the points of (4, 3) and (0, 3) is 4 units
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If these are Cartesian coordinates in the standard form (x,y), the distance is 7.28 units, roughly.
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Use Pythagoras: distance = √(difference_in_x^2 + difference_in_y^2) = √((6 - -3)^2 + (2 - -2)^2) = √(9^2 + 4^2) = √(81 + 16) = √97 ≈ 9.85 units
What is the distance between (4, -2) and (-1,6)?
In order to find the distance between two coordinates, you first need to find the difference between the x and y coordinates. In this case, the difference between the x coordinates is 3-(-2) = 5. The difference between the y coordinates is -4-5 = -9. To find the distance you add up the squares of these differences then find the square root. 52 = 25. -92 = 81. 25+81 = 106. Thus the distance is the square root of 106, or approximately 10.296