If these are Cartesian coordinates in the standard form (x,y), the distance is 7.28 units, roughly.
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Use Pythagoras: distance = √(difference_in_x^2 + difference_in_y^2) = √((6 - -3)^2 + (2 - -2)^2) = √(9^2 + 4^2) = √(81 + 16) = √97 ≈ 9.85 units
In order to find the distance between two coordinates, you first need to find the difference between the x and y coordinates. In this case, the difference between the x coordinates is 3-(-2) = 5. The difference between the y coordinates is -4-5 = -9. To find the distance you add up the squares of these differences then find the square root. 52 = 25. -92 = 81. 25+81 = 106. Thus the distance is the square root of 106, or approximately 10.296
What is the distance between (4, -2) and (-1,6)?
Just subtract the lowest number from the greatest number. For example, the distance between 3 and 8, is 8 - 3 = 5 units, the distance between -2 and 3, is 3 - (-2) = 3 + 2 = 5 units, the distance between -4 and -2, is -2 - (-4) = -2 + 4 = 2 units.
Different units for measuring distance are: 1.for distances on earth miles , kilometer, meter 2. Between galaxies - light year.
(-10--2)2+(8--7)2 = 289 and the square root of this is 17 Therefore the distance is 17 units in length.
Points: (-6, 1) and (-2, -2) Distance: 5 units
18 units ■
Using Pythagoras: 5 squared + 2 squared = √21 which is about 4.58.
Pythagoras! x-axis difference is 7 units, y-axis difference is 7 units, so distance is sqrt(7^2 + 7^2) ie sqrt 98 = 9.9 to first significant figure. true
Points: (-5, -2) and (3, 13)Distance works out as 17 units
Points: (2, 3) and (2, 7) Distance works out as: 4 units
the distance between two consecutive compressions or rarefactions of a light wave is called its wavelength.
Points: (1, -2) and (1, -5) Distance: 3 units by using the distance formula
3.61 units