You can always find the area of a triangle - by dividing the length of the base by 2, then multiplying that figure by the height.
yes
The area of ANY triangle is base x height. The height must be measured perpendicular to the base. In the case of an isosceles triangle, if you know only the length of the sides, you can figure out the height by Pythagoras' Theorem.
The remaining figure is the are of polygons that bounded by three dimensional figure .
Lateral Area= p times h p= perimeter of the base h=height of the figure Surface Area= Lateral Area + 2 times (B) B= Area of base
If the figure is a rectangle, the area is 60. If the figure is a triangle, the area is 30.
find the area of triangles(reflecting surfaces) and also the area of rectangle or square(base)and find the sum of both.
L=PH L=PH Lateral Area= (Perimeter of the base)(the height of the figure)
You can always find the area of a triangle - by dividing the length of the base by 2, then multiplying that figure by the height.
48in2. To find the area of any triangle - you divide the length of the base by 2, then multiply that figure by the height.
yes
If the figure is a rectangle, the area is 60. If the figure is a triangle, the area is 30.
The area of ANY triangle is base x height. The height must be measured perpendicular to the base. In the case of an isosceles triangle, if you know only the length of the sides, you can figure out the height by Pythagoras' Theorem.
Area of plane figure
The remaining figure is the are of polygons that bounded by three dimensional figure .
Lateral Area= p times h p= perimeter of the base h=height of the figure Surface Area= Lateral Area + 2 times (B) B= Area of base
It means the base in a 3D figure. For example, if it was a pyramid. the bottom part would be the base and you get the area of that base