To find five consecutive numbers that sum to 320, you can set up the equation where the middle number is ( x ). The five numbers would then be ( x - 2, x - 1, x, x + 1, x + 2 ). Their sum can be expressed as ( (x - 2) + (x - 1) + x + (x + 1) + (x + 2) = 5x ). Setting this equal to 320 gives ( 5x = 320 ), so ( x = 64 ). Therefore, the five consecutive numbers are 62, 63, 64, 65, and 66.
60,62,64,66,68
The four odd consecutive numbers that add up to 320 are 79, 81, 83, and 85. When you add these numbers together (79 + 81 + 83 + 85), they total 320. Each number is an odd integer, and they are consecutive in the sense that they follow one another in the sequence of odd numbers.
You need 5: 60, 62, 64, 66 & 68
To find 5% of 320, you can multiply 320 by 0.05 (which represents 5% as a decimal). This calculation results in 16. Therefore, 5% of 320 is 16.
The prime numbers (factors) of 320 are: 2 and 5
60, 62, 64, 66, 68
60,62,64,66,68
60.
320
You need 5: 60, 62, 64, 66 & 68
The numbers are 60, 62, 64, 66 and 68.
When you have this kind of question, try to break it down, maybe first by a 2 or 3 or 10. For your question, find 3 numbers whose product is 320, the answer is 4x8x10=320. So the 3 numbers are 4, 8, and 10.
To find the fifth number, you can use the formula for finding the average of a set of numbers. The sum of the 5 numbers is 82 * 5 = 410. The sum of the 4 known numbers is 80 * 4 = 320. Therefore, the fifth number can be found by subtracting the sum of the 4 known numbers from the sum of all 5 numbers: 410 - 320 = 90. So, the fifth number is 90.
1,2,4,5,8,10,16,20,32,40,64,80,160, and 320
To find 5% of 320, you can multiply 320 by 0.05 (which represents 5% as a decimal). This calculation results in 16. Therefore, 5% of 320 is 16.
The prime numbers (factors) of 320 are: 2 and 5
320