You need 5: 60, 62, 64, 66 & 68
60,62,64,66,68
The four odd consecutive numbers that add up to 320 are 79, 81, 83, and 85. When you add these numbers together (79 + 81 + 83 + 85), they total 320. Each number is an odd integer, and they are consecutive in the sense that they follow one another in the sequence of odd numbers.
To find five consecutive numbers that sum to 320, you can set up the equation where the middle number is ( x ). The five numbers would then be ( x - 2, x - 1, x, x + 1, x + 2 ). Their sum can be expressed as ( (x - 2) + (x - 1) + x + (x + 1) + (x + 2) = 5x ). Setting this equal to 320 gives ( 5x = 320 ), so ( x = 64 ). Therefore, the five consecutive numbers are 62, 63, 64, 65, and 66.
The prime numbers (factors) of 320 are: 2 and 5
320 is an even, rational and composite number
60,62,64,66,68
60.
The four odd consecutive numbers that add up to 320 are 79, 81, 83, and 85. When you add these numbers together (79 + 81 + 83 + 85), they total 320. Each number is an odd integer, and they are consecutive in the sense that they follow one another in the sequence of odd numbers.
60, 62, 64, 66, 68
The numbers are 60, 62, 64, 66 and 68.
To find five consecutive numbers that sum to 320, you can set up the equation where the middle number is ( x ). The five numbers would then be ( x - 2, x - 1, x, x + 1, x + 2 ). Their sum can be expressed as ( (x - 2) + (x - 1) + x + (x + 1) + (x + 2) = 5x ). Setting this equal to 320 gives ( 5x = 320 ), so ( x = 64 ). Therefore, the five consecutive numbers are 62, 63, 64, 65, and 66.
320
1,2,4,5,8,10,16,20,32,40,64,80,160, and 320
The prime numbers (factors) of 320 are: 2 and 5
320
32 X 10 X 1 8 X 40 X 1 on that last one you can switch the numbers around
the 2 numbers are 16 and 20. 16+20=36 and 16x20=320