If last two digits of a number are divisible by 4 then number is a multiple of 4 for a number with more than 21 digit
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To find a number that is a multiple of both 4 and 6 and ends with 8, we first need to find the least common multiple (LCM) of 4 and 6, which is 12. Any number that is a multiple of both 4 and 6 must also be a multiple of 12. Numbers that end with 8 and are multiples of 12 include 48, 108, 168, etc.
To find a 4-digit number that is divisible by both 8 and 9, we need to find a number that is a multiple of the least common multiple of 8 and 9, which is 72. Starting from the smallest 4-digit multiple of 72, which is 1008, we can find the next number by adding 72 until we reach a 4-digit number. Therefore, the smallest 4-digit number that is divisible by both 8 and 9 is 1008.
If the number is a multiple of 4 or 8 then it is divisible by 4 and 8 with no remainder If a number can be halved and the answer is even, it was divisible by 4.If the number can be halved twice and the answer is stilleven, it was divisble by 8.
Oh, dude, like, totally! So, to check if a number is a multiple of 4, you just need to see if it's divisible by 4 without any remainder. And guess what? 58 is not divisible by 4 because if you divide 58 by 4, you get 14 with a remainder of 2. So, in short, 58 is not a multiple of 4.