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How do you find the length of a rectangle knowing the perimeter and the width?
You divide the perimeter by the width and you get the lenght
How can you get the width when you have the perimeter and the length?
If the shape is a rectangle, then Perimeter = 2(Length + Width) So Width = Perimeter/2 - Length
How do you find the length of a rectangle if the perimeter is 40 and the width is 2inches?
perimeter = 2 x (length + width) ⇒ length + width = perimeter ÷ 2 ⇒ length = (perimeter ÷ 2) - width So to find the length of the given rectangle, subtract the width from half the perimeter is how to do it. IF you meant "What is the length..." then: length = perimeter ÷ 2 - width = 40 ÷ 2 - 2 in = 20 - 2 in = 18 in
What is one different way to to find the perimeter of a rectangle?
Length + length + width + width = perimeter. Length + width x 2 = perimeter
How do you find the width of a rectangle if you know the perimeter and the length?
Perimeter = 2 * width + 2 * length, so rearranging --> width = (Perimeter / 2) - length
How do you find the length of a rectangle knowing the perimeter and the width?
You divide the perimeter by the width and you get the lenght
How can you get the width when you have the perimeter and the length?
If the shape is a rectangle, then Perimeter = 2(Length + Width) So Width = Perimeter/2 - Length
How can you find the perimeter whithout knowing the width but knowing the length?
You can find the perimeter of any geometric shape knowing the length of one side if all sides are equal. For example: squares, hexagons, octagons and so on...
If the perimeter is 48 If the length is twic the width what is the length of rectangle?
perimeter = (2*length) + (2*width) length = 2*width so perimeter = (2*2*width) + 2*width = 6*width perimeter = 48 so you can figure out the width and length
How do you find the length of a rectangle if the perimeter is 40 and the width is 2inches?
perimeter = 2 x (length + width) ⇒ length + width = perimeter ÷ 2 ⇒ length = (perimeter ÷ 2) - width So to find the length of the given rectangle, subtract the width from half the perimeter is how to do it. IF you meant "What is the length..." then: length = perimeter ÷ 2 - width = 40 ÷ 2 - 2 in = 20 - 2 in = 18 in
What is one different way to to find the perimeter of a rectangle?
Length + length + width + width = perimeter. Length + width x 2 = perimeter
How do you get the area if you have the width and the perimeter?
Perimeter = 2 lengths + 2 widths 1/2 perimeter = length + width Length = 1/2 perimeter - width Area = length x width That's (1/2 perimeter - width) x (width) .
How do you find width when you have perimeter and length?
width = (perimeter-2*length)/2
How do you find the width of a rectangle if you know the perimeter and the length?
Perimeter = 2 * width + 2 * length, so rearranging --> width = (Perimeter / 2) - length
What can be concluded about a rectangles width if the ratio of length to perimeter is 1 to 3?
The width is half the length: The perimeter is twice the length plus twice the width. If the perimeter is 3 times the length, twice the width must be the length.
How can you calculate the length of a rectangle if the perimeter and the width are given?
Because the perimeter is lenght + length +width +width, you do perimeter - double the width, and then halve the remaining number. that should give you the length.
What is the width length and perimeter where the area equals 40 cm?
First of all, the area cannot be 40 cm since an area is 2-dimensional whereas the measure given is 1-dimensional. Next, the shape is not defined and so the width, length and perimeter are indeterminate. Even if you assume that the shape is a rectangle, the width, length and perimeter are indeterminate. On the basis that the length is greater than the width, all that you can say is that the length will be greater than or equal to sqrt(40) = 6.324555 (to 6 dp), the width will be 40 divided by that length and the perimeter will be twice their sum. Some examples: Length = 8, width = 5, perimeter = 26 Length = 10, width = 4, perimeter = 28 Length = 40, width = 1, perimeter = 82 Length = 4000, width = 0.01, perimeter = 8000.02 Length = 4,000,000, width = 0.00001, perimeter = 8,000,000.00002 and so on, without limit.
