0
The answer depends on the probability of WHICH event you want to find!
Wiki User
∙ 10y ago
Add your answer:
Earn +20 pts
A bag or marbles contains 8 red marbles and 5 green marbles Three marbles are drawn at random at the same time Find the probability that two are red and one is green?
There are 286 possible sets of three, (any 3 from 13). There are 28 pairs of reds and 5 possible greens so probability is 5 x 28 ie 140 out of 286 which is just under half (0.4895).
How does a bucket holds fifty marbles of red yellow and blue There are thirty red marbles and the probability of picking a yellow marble is three out of ten How many blue marbles are in the bucket?
soory dude or girl but this was just a joke question. but i hope you find what your looking for. by Michael Johnson
How do you find the probability when it involves marbles picked out of 2 different bags of marbles?
Two bags - 100 bags - The computation of probability is the same process - you take the number of desired results and divide by the number of possible results. The difference here is that the desired result sets do not intersect the possible result sets for the two bags, but the computation is the same - desired divided by possible.
How do you find the odd of picking a green marble 3 yellow 4 blue 6 green and 7 pink marbles?
The probability, in one draw, is 6/20 or 30%
A bag contains 8 marbles 4 are blue 3 are green and one is orange you draw out one marble and then another without replacing the first marble Find the probability of drawing 2 blue marbles?
Probability of drawing a blue marble first is 4 in 8 (or 50%) Probability of drawing a blue marble second is 3 in 7 (or 42.85714%) Probablility of drawing blue then blue is the two above multiplied 0.5 * 0.4285714 Which is 0.212142407 or 21% or One in Five.
What if there are 5 blue marbles 3 red marbles 5 white marbles and 7 yellow marbles in a bag determine the probability of not drawing a yellow one from the bag?
5, 3, 5, and 7 make a sum of 20. So 7/20 would be the probability of find a yellow one. Then, subtract 7 from 20 to find the probably of not finding a yellow one, which is 13/20, or 65%
If a bag contains 3 green marbles 5 blue marbles and 2 yellow marbles find the probability that the marble is blue?
Assuming that you're only taking out one marble, then:Your sample space --> 3 + 5 + 2 = 10The probability of getting a blue marble on the first draw is 3/10 or 0.3
A bag or marbles contains 8 red marbles and 5 green marbles Three marbles are drawn at random at the same time Find the probability that two are red and one is green?
There are 286 possible sets of three, (any 3 from 13). There are 28 pairs of reds and 5 possible greens so probability is 5 x 28 ie 140 out of 286 which is just under half (0.4895).
A bag contains 5 green marbles 3 yellow and 2 red marbles. What is the probability of picking three green marbles from the bag without replacement?
To find the answer to probability, first add all the things together (5+3+2=10), then, find the number of things you will be taking from the group of things (3), and put together as a fraction (3/10). So the final answer is 3/10, which is unlikely. :D
How does a bucket holds fifty marbles of red yellow and blue There are thirty red marbles and the probability of picking a yellow marble is three out of ten How many blue marbles are in the bucket?
soory dude or girl but this was just a joke question. but i hope you find what your looking for. by Michael Johnson
A bag contains 6 orange 7 green and 8 yellow marbles Find the probability of picking 3 yellow marbles if each marble is returned to the bag before the next marble is picked?
1 in 7
A bag contains 3 blue marbles and 4 red marbles. What is the probability that three randomly drawn marbles without replacement will all be red?
The probability of drawing 3 red marbles in a row from a bag of 3 blue and 4 red marbles without replacement is right at about 0.11 or about 11 in 100, if you want odds.Remember that probability is a pure number between zero (no chance - it's impossible) and 1 (it will happen - it's a certainty). A probability of 0.5 is a 50-50 shot, like a coin toss. We good? Let's move on.We have 7 marbles, and there is a 4 in 7 shot of getting a red marble in the first draw. There is a 3 in 6 shot the next draw since now we only have 6 marbles total (NO replacement) and only 3 red ones (we already drew a red one out). Similarly, there is a 2 in 5 shot of getting a third red one if the first two are red. The probability of the first action (getting a red marble on the first draw) is 4/7 or a probability of about 0.5714. Second draw, it's 3/6 or a probability of 0.5. Last, it's 2/5 or a probability of 0.40. To find the intersection of these probabilities, we just multiply them all together, and we'll get right at about 0.011 for a probability.
Can you find more experiments related to probability?
colors cards dice coin heads tails
How do you find the probability when it involves marbles picked out of 2 different bags of marbles?
Two bags - 100 bags - The computation of probability is the same process - you take the number of desired results and divide by the number of possible results. The difference here is that the desired result sets do not intersect the possible result sets for the two bags, but the computation is the same - desired divided by possible.
How do you find the odd of picking a green marble 3 yellow 4 blue 6 green and 7 pink marbles?
The probability, in one draw, is 6/20 or 30%
Explain how to find the probability of choosing a green marble from a bag of marbles containing 5 green 3 blue 6 red and 12 white?
If you pick only one marble from the bag, at random, it can be any one of 26 marbles. Out of these, 5 of the marbles are green. Thus, there are 26 possible outcomes out of which 5 are favourable - to the event that the marble is green. Therefore the probability of a green marble is 5/26. The calculations become more complicated if you consider choosing a green marble in several attempt: it depends on whether or not the marbles are replaced before the next one is picked.
A bag contains 8 marbles 4 are blue 3 are green and one is orange you draw out one marble and then another without replacing the first marble Find the probability of drawing 2 blue marbles?
Probability of drawing a blue marble first is 4 in 8 (or 50%) Probability of drawing a blue marble second is 3 in 7 (or 42.85714%) Probablility of drawing blue then blue is the two above multiplied 0.5 * 0.4285714 Which is 0.212142407 or 21% or One in Five.
