The answer depends on the probability of WHICH event you want to find!
There are 286 possible sets of three, (any 3 from 13). There are 28 pairs of reds and 5 possible greens so probability is 5 x 28 ie 140 out of 286 which is just under half (0.4895).
soory dude or girl but this was just a joke question. but i hope you find what your looking for. by Michael Johnson
Two bags - 100 bags - The computation of probability is the same process - you take the number of desired results and divide by the number of possible results. The difference here is that the desired result sets do not intersect the possible result sets for the two bags, but the computation is the same - desired divided by possible.
The probability, in one draw, is 6/20 or 30%
Probability of drawing a blue marble first is 4 in 8 (or 50%) Probability of drawing a blue marble second is 3 in 7 (or 42.85714%) Probablility of drawing blue then blue is the two above multiplied 0.5 * 0.4285714 Which is 0.212142407 or 21% or One in Five.
5, 3, 5, and 7 make a sum of 20. So 7/20 would be the probability of find a yellow one. Then, subtract 7 from 20 to find the probably of not finding a yellow one, which is 13/20, or 65%
Assuming that you're only taking out one marble, then:Your sample space --> 3 + 5 + 2 = 10The probability of getting a blue marble on the first draw is 3/10 or 0.3
There are 286 possible sets of three, (any 3 from 13). There are 28 pairs of reds and 5 possible greens so probability is 5 x 28 ie 140 out of 286 which is just under half (0.4895).
To calculate the probability of not drawing two green marbles, we first find the probability of drawing a green marble on the first draw, which is 5/20 since there are 5 green marbles out of a total of 20 marbles. The probability of not drawing a green marble on the first draw is 1 - 5/20 = 15/20. Since the marbles are replaced, the probability of not drawing a green marble on the second draw is also 15/20. Therefore, the probability of not drawing two green marbles is (15/20) * (15/20) = 225/400 = 9/16 or 56.25%.
To find the answer to probability, first add all the things together (5+3+2=10), then, find the number of things you will be taking from the group of things (3), and put together as a fraction (3/10). So the final answer is 3/10, which is unlikely. :D
soory dude or girl but this was just a joke question. but i hope you find what your looking for. by Michael Johnson
To find the density of marbles, you would measure the mass of a certain number of marbles using a balance scale, then calculate the volume by either measuring the dimensions and using a formula for the shape of the marbles or by displacement method with water. Finally, divide the mass by the volume to determine the density of the marbles.
The probability of drawing 3 red marbles in a row from a bag of 3 blue and 4 red marbles without replacement is right at about 0.11 or about 11 in 100, if you want odds.Remember that probability is a pure number between zero (no chance - it's impossible) and 1 (it will happen - it's a certainty). A probability of 0.5 is a 50-50 shot, like a coin toss. We good? Let's move on.We have 7 marbles, and there is a 4 in 7 shot of getting a red marble in the first draw. There is a 3 in 6 shot the next draw since now we only have 6 marbles total (NO replacement) and only 3 red ones (we already drew a red one out). Similarly, there is a 2 in 5 shot of getting a third red one if the first two are red. The probability of the first action (getting a red marble on the first draw) is 4/7 or a probability of about 0.5714. Second draw, it's 3/6 or a probability of 0.5. Last, it's 2/5 or a probability of 0.40. To find the intersection of these probabilities, we just multiply them all together, and we'll get right at about 0.011 for a probability.
Well, honey, if you're reaching into that bag three times and each time you're pulling out a yellow marble and then putting it back in, the probability of picking a yellow marble each time is 8/21. Multiply that by itself three times because you're picking three marbles, and you get a probability of 512/9261. So, good luck with those yellow marbles, darlin'!
colors cards dice coin heads tails
Two bags - 100 bags - The computation of probability is the same process - you take the number of desired results and divide by the number of possible results. The difference here is that the desired result sets do not intersect the possible result sets for the two bags, but the computation is the same - desired divided by possible.
The probability, in one draw, is 6/20 or 30%