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What is the probablility of picking a green marble at random from a box that contains only 11 blue marbles?
The probability of picking a green marble from a box that only contains blue marbles is zero.
In a bag of marbles you have three green two yellow six blue and nine red marbles. What is the probability of picking a red marble from the bag?
To find the probability of picking a red marble, first determine the total number of marbles in the bag, which is 3 (green) + 2 (yellow) + 6 (blue) + 9 (red) = 20 marbles. The number of red marbles is 9. Therefore, the probability of picking a red marble is the number of red marbles divided by the total number of marbles, which is 9/20 or 0.45.
A bag has 7 blue marbles and 8 purple marbles.What is the probability of picking a blue marble then a purple marble without replacing?
7/15 for blue marbles and 8/14 for the purple marbles this is dependent probability
There are 6 brown 5 blue and 2 orange marbles in a hat. What is the probability of picking two orange marbles in a row without returning the marbles back to the hat?
To find the probability of picking two orange marbles in a row without replacement, first note there are a total of 13 marbles (6 brown + 5 blue + 2 orange). The probability of picking the first orange marble is ( \frac{2}{13} ). After removing one orange marble, there is now 1 orange marble left and a total of 12 marbles remaining. Therefore, the probability of picking the second orange marble is ( \frac{1}{12} ). The combined probability of both events is ( \frac{2}{13} \times \frac{1}{12} = \frac{2}{156} = \frac{1}{78} ).
42 red marbles 17 green marbles 27 blue marbles what is the experimental probability of picking a green marble?
if you pick one marble at random, the odds are 17/(42+17+27) or 17/86 or about 20%
What is the probability of picking a red marble and then a blue marble?
None, if all the marbles that you have are yellow!
There is a bag of marbles 10 are red 15 are purple and 25 are yellow what is the probability of picking a purple marble?
3/10 or 0.3 is the probability of picking a purple marble.
A bag contains 3 red marbles 5 blue marbles 8 yellow marbles and 4 black marbles what is the theoretical probability of randomly picking each color marble?
The theoretical probability of randomly picking each color marble is the number of color marbles you have for each color, divided by the total number of marbles. For example, the probability of selecting a red marble is 3/20.
What is the probablility of picking a green marble at random from a box that contains only 11 blue marbles?
The probability of picking a green marble from a box that only contains blue marbles is zero.
In a bag of marbles you have three green two yellow six blue and nine red marbles. What is the probability of picking a red marble from the bag?
To find the probability of picking a red marble, first determine the total number of marbles in the bag, which is 3 (green) + 2 (yellow) + 6 (blue) + 9 (red) = 20 marbles. The number of red marbles is 9. Therefore, the probability of picking a red marble is the number of red marbles divided by the total number of marbles, which is 9/20 or 0.45.
A bag has 7 blue marbles and 8 purple marbles.What is the probability of picking a blue marble then a purple marble without replacing?
7/15 for blue marbles and 8/14 for the purple marbles this is dependent probability
What is the probability of picking a blue marble from a bag of 4 red marbles 6 blue marbles and 1 white marble?
11 marbles total and 6 are blue so probability is 6/11
If you have 6 red marbles 3 yellow marbles and 5 green marbles in a bag what is the probability of picking a blue marble out?
0No blue marbles in the bag.
There are 6 brown 5 blue and 2 orange marbles in a hat. What is the probability of picking two orange marbles in a row without returning the marbles back to the hat?
To find the probability of picking two orange marbles in a row without replacement, first note there are a total of 13 marbles (6 brown + 5 blue + 2 orange). The probability of picking the first orange marble is ( \frac{2}{13} ). After removing one orange marble, there is now 1 orange marble left and a total of 12 marbles remaining. Therefore, the probability of picking the second orange marble is ( \frac{1}{12} ). The combined probability of both events is ( \frac{2}{13} \times \frac{1}{12} = \frac{2}{156} = \frac{1}{78} ).
A bag contains 6 orange 7 green and 8 yellow marbles Find the probability of picking 3 yellow marbles if each marble is returned to the bag before the next marble is picked?
Well, honey, if you're reaching into that bag three times and each time you're pulling out a yellow marble and then putting it back in, the probability of picking a yellow marble each time is 8/21. Multiply that by itself three times because you're picking three marbles, and you get a probability of 512/9261. So, good luck with those yellow marbles, darlin'!
42 red marbles 17 green marbles 27 blue marbles what is the experimental probability of picking a green marble?
if you pick one marble at random, the odds are 17/(42+17+27) or 17/86 or about 20%
A bag contains 3 blue marbles 7 red marbles and 5 yellow marbles If Joe picks 1 marble from the bag at random what is the probability that it will be blue?
1 in 15 chances that the marble will be blue, because there are 15 marbles all together in a bag, and you are only picking one out of it.
