Place it gently on a scale.
The ratio of the length of the side in the big triangle to the length of the corresponding side in the little triangle is the scale factor.
To find the actual length of the fence, multiply the length on the blueprint by the scale. Given a scale of 1:40 and a length of 6 inches on the blueprint, the calculation would be 6 inches × 40 = 240 inches. Therefore, the actual length of the fence is 240 inches, or 20 feet.
To determine the length of the object in the drawing, use the scale of 3 inches for every 4 feet. First, find the ratio of the actual length to the scale length: ( 24 \text{ ft} \div 4 \text{ ft} = 6 ). Then, multiply this ratio by the scale length: ( 6 \times 3 \text{ in} = 18 \text{ in} ). Therefore, the length of the object in the drawing is 18 inches.
The scale.
how to do a scale factor of cylinder is that you find the base and the height and the length of A area hope you like my examples.
Place it gently on a scale.
The ratio of the length of the side in the big triangle to the length of the corresponding side in the little triangle is the scale factor.
To find the scale factor of two triangles, look first for one pair of corresponding sides--one side from the smaller triangle and the corresponding side from the larger triangle. Divide the larger side length by the smaller side length, and that quotient is your scale factor.
You divide a length of one polygon by the corresponding length in the other polygon. Any length will do, as long as you use the corresponding length in both.
Divide any length of any part of one of the objects to the length of the corresponding part of the other object.
To find the actual length of the fence, multiply the length on the blueprint by the scale. Given a scale of 1:40 and a length of 6 inches on the blueprint, the calculation would be 6 inches × 40 = 240 inches. Therefore, the actual length of the fence is 240 inches, or 20 feet.
To determine the length of the object in the drawing, use the scale of 3 inches for every 4 feet. First, find the ratio of the actual length to the scale length: ( 24 \text{ ft} \div 4 \text{ ft} = 6 ). Then, multiply this ratio by the scale length: ( 6 \times 3 \text{ in} = 18 \text{ in} ). Therefore, the length of the object in the drawing is 18 inches.
The length on the map that represents 80m with a scale of 1cm to 5m would be 16cm. To find this, divide 80m by 5m to get 16. Then, scale it down to one centimeter.
The scale.
The scale factor.
1cm:15m If 1 cm = 20 m then 6 cm = 120 m real length