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How do you find theta?
You shoot a cannon with a vi of 18 m/s. You need to get it 16m and over a 10m wall. The acceleration in the x is 0 and in the y it is gravity. The question is at what angle theta can you shoot the cannon over the fence and 16 meters away. How do I find theta?
What is whole under root of sec theta - 1 over sec theta 1?
Ut is equual to tan(theta) / (sec(theta) + 1)
What is the equivalent of sine theta over secant theta?
For such simplifications, it is usually convenient to convert any trigonometric function that is not sine or cosine, into sine or cosine. In this case, you have: sin theta / sec theta = sin theta / (1/cos theta) = sin theta cos theta.
What is the mathematical proof of sine theta over theta is equal to 1?
There is none because it is not true.
If the area of a circle is 25 square units what is the radius of the circle?
area equals pi r squared therefor r squared equals area over pi. Now find square root of r squared and you have "R" (radius) = 2.821
How do you solve sin2 theta if sin theta equals 3 over 5 and theta is in the first quadrant?
If sin (theta) is 3/5, then sin2 (theta) is (3/5)2, or 9/25.
How do you find theta?
You shoot a cannon with a vi of 18 m/s. You need to get it 16m and over a 10m wall. The acceleration in the x is 0 and in the y it is gravity. The question is at what angle theta can you shoot the cannon over the fence and 16 meters away. How do I find theta?
What is sec theta - 1 over cos theta?
zero
What equals force and distance?
Work equals force multiplied by distance. It is a measure of the energy transferred to or from an object when a force is applied over a certain distance. Mathematically, work = force x distance x cos(theta), where theta is the angle between the force and the direction of motion.
What is whole under root of sec theta - 1 over sec theta 1?
Ut is equual to tan(theta) / (sec(theta) + 1)
What is the equivalent of sine theta over secant theta?
For such simplifications, it is usually convenient to convert any trigonometric function that is not sine or cosine, into sine or cosine. In this case, you have: sin theta / sec theta = sin theta / (1/cos theta) = sin theta cos theta.
What is the mathematical proof of sine theta over theta is equal to 1?
There is none because it is not true.
If the area of a circle is 25 square units what is the radius of the circle?
area equals pi r squared therefor r squared equals area over pi. Now find square root of r squared and you have "R" (radius) = 2.821
How do you find the height of a right angle?
Assuming you know the angle of ascension, and the base, you can calculate the height by recalling that tangent theta is height over base. Simple algebra from there: height is tangent theta times base.
What is the difference between sin cos and tan?
In a right triangle, the right angle is formed by sides a and b. Side c is the hypotenuse.Theta is the interior angle that joins (let's say) sides b and c. The sin of theta is the length of a over the length of c. The cos of theta is the length of b over the length of c. The tan of theta is the length of a over the length of b.Sin theta= opposite divided by hypotenuse. Cos theta=adjacent divided by hypotenuse. Tan theta=opposite over adjacent.(Sin1-Cos1)-Tan1=-1.25623905Sorry, that was a mathematician's joke.
Write the curve x3 y3 3axy in polar form Hence find the area encircled by its loop?
To convert the curve (x^3 + y^3 = 3axy) into polar form, we use the substitutions (x = r\cos\theta) and (y = r\sin\theta). This gives us the polar equation (r^3(\cos^3\theta + \sin^3\theta) = 3ar^2\cos\theta\sin\theta), which simplifies to (r = \frac{3a\cos\theta\sin\theta}{\cos^3\theta + \sin^3\theta}). To find the area encircled by the loop, we can use the formula for the area in polar coordinates, (A = \frac{1}{2} \int_{\theta_1}^{\theta_2} r^2 d\theta). Evaluating this integral over one loop (typically from (0) to (\frac{\pi}{2}) for the symmetric shape) yields the area (A = \frac{3\pi a^2}{8}).
What is 46x X 87y over the square-root of 90?
If you move that 46x over the equals, and if you square both sides, you can get rid of that square root, and do the equation normally. do the math
