You shoot a cannon with a vi of 18 m/s. You need to get it 16m and over a 10m wall. The acceleration in the x is 0 and in the y it is gravity. The question is at what angle theta can you shoot the cannon over the fence and 16 meters away. How do I find theta?
The expression "cot theta = 1.5 sin theta" can be rewritten using the definitions of trigonometric functions. Since cotangent is the reciprocal of tangent, we have cot(theta) = cos(theta) / sin(theta). Therefore, the equation becomes cos(theta) / sin(theta) = 1.5 sin(theta), leading to cos(theta) = 1.5 sin^2(theta). This relationship can be used to find specific values of theta that satisfy the equation.
cos(theta) = 0.7902 arcos(0.7902) = theta = 38 degrees you find complimentary angles
The length of the arc is r*theta where r is the radius and theta the angle subtended by the arc at the centre of the circle. If you do not know theta (or cannot derive it), you cannot find the length of the arc.
sine[theta]=opposite/hypotenuse=square root of (1-[cos[theta]]^2)
tan(theta) = 1 then theta = tan-1(1) + n*pi where n is an integer = pi/4 + n*pi or pi*(1/4 + n) Within the given range, this gives theta = pi/4 and 5*pi/4
The answer depends on what theta represents!
Cotan(theta) is the reciprocal of the tan(theta). So, cot(theta) = 1/2.
No.
Since theta is in the second quadrant, sin(theta) is positive. sin2(theta) = 1 - cos2(theta) = 0.803 So sin(theta) = +sqrt(0.803) = 0.896.
tan2(theta) + 5*tan(theta) = 0 => tan(theta)*[tan(theta) + 5] = 0=> tan(theta) = 0 or tan(theta) = -5If tan(theta) = 0 then tan(theta) + cot(theta) is not defined.If tan(theta) = -5 then tan(theta) + cot(theta) = -5 - 1/5 = -5.2
96 degrees Let theta represent the measure of the angle we are trying to find and theta' represent the measure of its supplement. From the problem, we know: theta=theta'+12 Because supplementary angles sum to 180 degrees, we also know: theta+theta'=180 Substituting the value from theta in the first equation into the second, we get: (theta'+12)+theta'=180 2*theta'+12=180 2*theta'=180-12=168 theta'=168/2=84 Substituting this value for theta' back into the first equation, we get: theta+84=180 theta=180-84=96
The expression "cot theta = 1.5 sin theta" can be rewritten using the definitions of trigonometric functions. Since cotangent is the reciprocal of tangent, we have cot(theta) = cos(theta) / sin(theta). Therefore, the equation becomes cos(theta) / sin(theta) = 1.5 sin(theta), leading to cos(theta) = 1.5 sin^2(theta). This relationship can be used to find specific values of theta that satisfy the equation.
cos(theta) = 0.7902 arcos(0.7902) = theta = 38 degrees you find complimentary angles
The length of the arc is r*theta where r is the radius and theta the angle subtended by the arc at the centre of the circle. If you do not know theta (or cannot derive it), you cannot find the length of the arc.
sine[theta]=opposite/hypotenuse=square root of (1-[cos[theta]]^2)
To find the limit of a cardioid, you can analyze its parametric equations or polar form. A cardioid can be represented in polar coordinates as ( r(\theta) = 1 - \sin(\theta) ) or ( r(\theta) = 1 + \sin(\theta) ). To find the limit as ( r ) approaches a particular value, evaluate the function as ( \theta ) varies, and identify the behavior of ( r ) for specific angles. The limits typically involve examining the values of ( r ) as ( \theta ) approaches critical points, such as ( 0 ), ( \frac{\pi}{2} ), or ( \pi ).
2 sin (Θ) + 1 = 0sin (Θ) = -1/2Θ = 210°Θ = 330°