The area of any hexagon is 6(0.5)(L)(L sin 60o) = 3L2 sin 60o, where L is the length of one side and is also the radius of the circumscribed circle.
Half the square root of the square radius equals the circle radius.
Approximately 5.66x5.66 in. Or root32 x root32
(3x2 √3) / 2 Where x is the length of a side, given that the hexagon is a regular hexagon. However, if the hexagon is is not regular, you will have to find the area of the two trapeziums within the hexagon, find the area of them, and add them together.
There is a ninja behind you
The answer in 6.... draw an angular bisector from one of the angles to the centre of circle then draw a perpendicular from the centre of circle. Those to lines will form a triangle... use trigonometry and find the length of the perpendicular, which is also a radius... double the radius and u will get the diagonal for the square... using formula :- (Side)^2 + (Side)^2 = (Diagonal)^2, find the side of square and square the answer, which will give you your final answer
You would have to use a couple of formulas to do this. It would basically be 374.4 cm in area but first you would have to find the base and the height.
Find the dimensions of the rectangle of largest area that can be inscribed in a circle of radius a in C programming
If yo have the area of the circle, the square is irrelevant. Radius = sqrt(Area/pi)
112cm2
usually: 1/2 b x h
1
124
Half the square root of the square radius equals the circle radius.
The surface area of a hexagon is the same as its area. You will normally need to split the hexagon into triangles, find their area and sum these.
(3x2 √3) / 2 Where x is the length of a side, given that the hexagon is a regular hexagon. However, if the hexagon is is not regular, you will have to find the area of the two trapeziums within the hexagon, find the area of them, and add them together.
To find the circumference of a circle in rhombus you eat SH*t .
Approximately 5.66x5.66 in. Or root32 x root32