112cm2
Find the dimensions of the rectangle of largest area that can be inscribed in a circle of radius a in C programming
If yo have the area of the circle, the square is irrelevant. Radius = sqrt(Area/pi)
The area of square is : 100.0
area of a circle = area of a rectangle(parallelogram) formed by the sectors of circle with pi as length and radius as bradth.
It is 374.12 sq inches.
Find the dimensions of the rectangle of largest area that can be inscribed in a circle of radius a in C programming
6.5 units
It is 2*r^2.
The largest rectangle would be a square. If the circle has radius a, the diameter is 2a. This diameter would also be the diameter of a square of side length b. Using the Pythagorean theorem, b2 + b2 = (2a)2. 2b2 = 4a2 b2 = 2a2 b = √(2a2) or a√2 = the length of the sides of the square The area of a square of side length b is therefore (√(2a2))2 = 2a2 which is the largest area for a rectangle inscribed in a circle of radius a.
The center of the rectangle to the corner of the rectangle is the radius of the circle. That can be found using the distance formula sqrt((5/2)^2+(12/2)^2) = 6.5 = r 5/2 is half the height of the rectangle and 12/2 is half the height of the rectangle. radius = 6.5
Approximately 5.66x5.66 in. Or root32 x root32
Assuming there is no border around the circle, then doubling the radius will give the length and width of a square (28 x 28 = 784cm2). The problem in your question is that you state it is a rectangle. Which means that the rectangle must be longer in length then width!
If you know the length of the side of the (regular) hexagon to be = a the radius r of the inscribed circle is: r = a sqrt(3)/2
The radius of a circle inscribed in a regular hexagon equals the length of one side of the hexagon.
radius
Yes.
There are different formula for: Height, Area, Perimeter, Angle, Length of Median Radius of inscribed circle Perimeter of inscribed circle Area of inscribed circle etc.