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Can you find the area of a rectangle if the problem doesn't show you the base and height?
The one alternative to find the area of a rectangle is when you are given the length of one diagonal and its slope.
How can you find the area of a rectangle if the given is the perimeter and the diagonal?
First divide the perimeter by 2 then subtract the diagonal from this. The number left with must equal two numbers that when squared and added together equals the diagonal when squared (Pythagoras' theorem) These numbers will then be the length and height of the rectangle.
How do you find the area of a rectangle from diagonal and 1 angle?
The diagonal multiplied by sin(angle) gives one side of the rectangle and the diagonal times cos(theta) gives the other. So the area is (diagonal)2 x cos(theta) x sin(theta).
How do you find the area of a rectangle given the length and diagonal?
The area of a rectangle is length times width. If you have the length and a diagonal, you will first have to figure out the width, using the formula of Pythagoras. length2 + width2 = diagonal2; solving for width: width = square root of (diagonal2 - length2). Once you have the width, just multiply lenght x width.
How to find the area of a rectangle from diagonal?
You need to know more...either the angle or the length of one of the sides.
Can you find the area of a rectangle if the problem doesn't show you the base and height?
The one alternative to find the area of a rectangle is when you are given the length of one diagonal and its slope.
How do you find the area of a rectangle with the diagonal of 13 and a width of 5?
if a rectangle has width of 5 and diagonal with lenght of 13, what is the area of the rectangle? Use Pythagoras' theorem to find the length of the rectangle which will be 12 5*12 = 60 square units
How do you find the length of rectangle diagonally by using the area given?
You can't. Suppose for instance your rectangle is 1xA, then the diagonal length is sqrt(1+A**2). But if your rectangle is sqrt(A)xsqrt(A) then your diagonal length is sqrt(2*A). The only thing one can say for sure is that the diagonal length is at least sqrt(2*A).
How can you find the area of a rectangle if the given is the perimeter and the diagonal?
First divide the perimeter by 2 then subtract the diagonal from this. The number left with must equal two numbers that when squared and added together equals the diagonal when squared (Pythagoras' theorem) These numbers will then be the length and height of the rectangle.
How do you find the area of a rectangle if you only know the width and the diagonal?
Suppose the width is W and the diagonal is D.Then, by Pythagoras's theorem, the length, L, is given by L = sqrt(D^2 - W^2).And then, area = L*W.
How do you find the area of a rectangle from diagonal and 1 angle?
The diagonal multiplied by sin(angle) gives one side of the rectangle and the diagonal times cos(theta) gives the other. So the area is (diagonal)2 x cos(theta) x sin(theta).
The diagonal of the rectangle is 26m and its perimeter is 68m. Find its area?
240 sq m
How do you find the area of a rectangle given the length and diagonal?
The area of a rectangle is length times width. If you have the length and a diagonal, you will first have to figure out the width, using the formula of Pythagoras. length2 + width2 = diagonal2; solving for width: width = square root of (diagonal2 - length2). Once you have the width, just multiply lenght x width.
How do you find the dimension of a rectangle when area is given?
Divide its area by a given side
How to find the area of a rectangle from diagonal?
You need to know more...either the angle or the length of one of the sides.
How do you find the area of rectangle given its perimeter?
You cannot.
How do you find the length of a rectangle given the width and area?
the area of a rectangle = length x widthwe can rearrange this to give uslength of a rectangle = area/ width
