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2 x 2 = 4. 4 is a constant. The derivative of a constant is always 0. Therefore, The derivative of 2 x 2 is zero.

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Q: Find the derivative of 2x2
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The total derivative of 2x2 plus 7?

4x


What is the derivative of 2x2 plus 3x plus 7?

d/dx 2x2+3x+7=4x+3


What is the derivative of 1 over 2 x?

d/dx(1/2x) = -1/(2x2)


What is the vertex of -2x2 plus 2x plus 3?

Since this question is in the calculus section, I'm assuming you know how to take the derivative. We know that y = -2x2 + 2x + 3 is a parabola, so it has one vertex, which is a minimum. We can use the first derivative test to find this extreme point.First, take the derivative:y' = -4x + 2Next, set y' equal to zero:0 = -4x + 2Then solve for x:4x = 2x = 2This is the x-coordinate of the vertex. To find the y-coordinate, plug x = 2 back into the original equation:y = -2x2 + 2x + 3y = -8 + 4 + 3y = -1So the vertex is at (2, -1).


How do you find the vertex of 2x2 plus 4 plus 1?

2x2 + 4 + 1 = 2x2 + 5 So, the vertex is (0, 5)

Related questions

What is the derivative of -2X2?

(-2 x2)' = -4 x


What do derivative classifiers do?

Cos-1 2x2-1


The total derivative of 2x2 plus 7?

4x


What must Derivative classifiers do?

Cos-1 2x2-1


Derivative classifiers must what?

Cos-1 2x2-1


What is the derivative of 2x2 plus 3x plus 7?

d/dx 2x2+3x+7=4x+3


What is the derivative of 2x-squared plus 4x plus 8?

The derivative of 2x2 + 4x + 8 is 4x+4.


What is the derivative of 1 over 2 x?

d/dx(1/2x) = -1/(2x2)


What is the anti-derivative of x2 1x?

The antiderivative of x2 + x is 1/3x3 + 1/2x2 + C.


Find the second derivative for the square root of x2 - 3?

-1


What is the vertex of -2x2 plus 2x plus 3?

Since this question is in the calculus section, I'm assuming you know how to take the derivative. We know that y = -2x2 + 2x + 3 is a parabola, so it has one vertex, which is a minimum. We can use the first derivative test to find this extreme point.First, take the derivative:y' = -4x + 2Next, set y' equal to zero:0 = -4x + 2Then solve for x:4x = 2x = 2This is the x-coordinate of the vertex. To find the y-coordinate, plug x = 2 back into the original equation:y = -2x2 + 2x + 3y = -8 + 4 + 3y = -1So the vertex is at (2, -1).


How do you find the vertex of 2x2 plus 4 plus 1?

2x2 + 4 + 1 = 2x2 + 5 So, the vertex is (0, 5)