First, find the LCM (Least Common Multiple) of the three intercepts.
Second, divide the LCM by the X-Intercept. Repeat for the Y- and Z-Intercepts.
Third, take the three values, and put them together like this:
(LCM/X-Intercept)x+(LCM/Y-Intercept)y+(LCM/Z-Intercept)z=LCM
If it need it, you can simplify it.
For example, if you have a plane with the intercepts (5, 0, 0), (0, 2, 0), and (0, 0, 3), the the LCM would be 30, so you would have:
(30/5)x+(30/2)y+(30/3)z=30
6x+15y+10z=30
When you graph the quadratic equation, you have three possibilities... 1. The graph touches x-axis once. Then that quadratic equation only has one solution and you find it by finding the x-intercept. 2. The graph touches x-axis twice. Then that quadratic equation has two solutions and you also find it by finding the x-intercept 3. The graph doesn't touch the x-axis at all. Then that quadratic equation has no solutions. If you really want to find the solutions, you'll have to go to imaginary solutions, where the solutions include negative square roots.
Set 'x' equal to zero, and solve the remaining equation for 'y'.
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If you have two equations give AND one parametric equation why do you need to find yet another equation?
In the same coordinate space, i.e. on the same set of axes: -- Graph the first equation. -- Graph the second equation. -- Graph the third equation. . . -- Rinse and repeat for each equation in the system. -- Visually examine the graphs to find the points (2-dimension graph) or lines (3-dimension graph) where all of the individual graphs intersect. Since those points or lines lie on the graph of each individual graph, they are the solution to the entire system of equations.
You find the equation of a graph by finding an equation with a graph.
well, you find the two cooridinates on the plane and then graph them! KINDA EASY!
from a table to a graph just graph x and y (on a coordinate plane) from table to equation find the slope of the line and the y intercept. your equation should be in the form y=mx+b where m is the slope and b is the y intercept
They are all the points where the graph crosses (or touches) the x-axis.
When you graph the quadratic equation, you have three possibilities... 1. The graph touches x-axis once. Then that quadratic equation only has one solution and you find it by finding the x-intercept. 2. The graph touches x-axis twice. Then that quadratic equation has two solutions and you also find it by finding the x-intercept 3. The graph doesn't touch the x-axis at all. Then that quadratic equation has no solutions. If you really want to find the solutions, you'll have to go to imaginary solutions, where the solutions include negative square roots.
You can either measure or estimate the coordinates visually from the graph, or solve the equation underlying the graph.
Set 'x' equal to zero, and solve the remaining equation for 'y'.
Select any value for one of the variables in the graph and solve the equation to get the other variable.
Bggvgvvguo
If you have two equations give AND one parametric equation why do you need to find yet another equation?
In the same coordinate space, i.e. on the same set of axes: -- Graph the first equation. -- Graph the second equation. -- Graph the third equation. . . -- Rinse and repeat for each equation in the system. -- Visually examine the graphs to find the points (2-dimension graph) or lines (3-dimension graph) where all of the individual graphs intersect. Since those points or lines lie on the graph of each individual graph, they are the solution to the entire system of equations.
Solve f(x) =0 or y = 0 (depending on how the equation is given).