divide by the gradient
Draw a tangent to the curve at the point where you need the gradient and find the gradient of the line by using gradient = up divided by across
Yes beccause: (y1-y2)/(x1-x2) = gradient
The gradient of a line is the same as the slope of a line. It will tell someone measuring the line how straight the line is.
Select two values of x: (x1 and x2) within the domain. Solve the equation of the line to find the corresponding values for y: (y1 and y2). Then the gradient = (y1 - y2) / (x1 - x2)
divide by the gradient
basically the reciprocal of the original lines gradient is going to be the gradient for the perpendicular line (remember the signs should switch). For example if i had a line with the gradient of 3, then the gradient of the perpendicular line will be -1over3. But if the line had the gradient of -3, then the line perpendicular to that line will have the gradient 1over3.
Draw a tangent to the curve at the point where you need the gradient and find the gradient of the line by using gradient = up divided by across
-5/7
Yes beccause: (y1-y2)/(x1-x2) = gradient
The gradient of a line is the same as the slope of a line. It will tell someone measuring the line how straight the line is.
The higher the gradient, the more steeper the line will be.
The gradient of a straight line cannot be defined- it's infinity.
Select two values of x: (x1 and x2) within the domain. Solve the equation of the line to find the corresponding values for y: (y1 and y2). Then the gradient = (y1 - y2) / (x1 - x2)
It is the gradient (slope) of the line.
If necessary, rearrange the linear equation so that it is in the slope-intercept form: y = mx + c Then the gradient of the line is m.
It is its slope or gradient.