An isosceles triangle has 2 equal base angles and its height is perpendicular from its apex to the centre of its base
For all triangles: area = 1/2 * base * height
To find the circumradius of an isosceles triangle, the formula is:1/8[(a^2/h)+4h]in which h is the height of the triangle and a is the base of the triangle.
well it seems to me that i don't have a CLUE what your talking about !
For all triangles: area = 1/2 * base * height
An isosceles triangle has 2 equal base angles and its height is perpendicular from its apex to the centre of its base
(1/2) * base * height
i can
Yes if the isosceles triangle is a right isosceles triangle because that leg opposite the hypotenuse is the height
For all triangles: area = 1/2 * base * height
To find the circumradius of an isosceles triangle, the formula is:1/8[(a^2/h)+4h]in which h is the height of the triangle and a is the base of the triangle.
Area = 1/2*(sum of the 2 parallel sides)*height
By using Pythagoras' theorem.
well it seems to me that i don't have a CLUE what your talking about !
For all triangles: area = 1/2 * base * height
To find the area of any triangle... divide the length of the base by 2... then multiply the result by the height.
The area of ANY triangle is base x height. The height must be measured perpendicular to the base. In the case of an isosceles triangle, if you know only the length of the sides, you can figure out the height by Pythagoras' Theorem.