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Say you know the surface area of said cube is 450. cubes have six sides, so you need to find the area of one of them by doing 450/6 = 75. Think about 2d geometry. If you have a rectangle, how do you find it's diagonal? Using the Pythagorean theorem 'a' squared plus 'b' squared equals 'c' squared (keep in mind a + b doesn't equal c). so to get the interior diagonal, you need the diagonal of one of the faces and the length of a side. then re-use pythagorean to get it.
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If a diagonal of a cube is known how to find the volume of the cube?
If the diagonal is d thenV = [d/sqrt(3)]^3
Is the cube diagonal and plane diagonal of a cube the same?
No.
What is the length in inches of a diagonal of a 20 foot cube?
12 inches = 1 foot. 240 inches = 20 feet. Use Pythagoras' theorem to find the diagonal of one of the faces of the cube. 2402+2402 = 115200. The square root of 115200 is 339.411255 Therefore the diagonal of the cube is 339.411255 inches or 339 inches correct to three significant figures Incidentally, by using the above answer and Pythagoras' theorem we can also work out the length of the longest internal diagonal within the cube which works out exactly as 340 inches.
How can I figure the dimensions of a perfect cube if the hypotenuse through the center of the cube is 35cm?
Somehow I messed up andused 31 instead of 35 That is why you are receiving an improvement Do a Google search for Diagonal of a cube Find this website. mathcentral.uregina.ca/QQ/database/QQ.09.04/brett1.HTML - Draw a cube You will see how to find the diagonal of a cube. You use Pythagorean Theorem Draw a cube Label each side as s Draw the diagonal of the base of the cube Diagonal of base = (s^2 + s^2 )^0.5 Let the diagonal of the base be the horizontal side of the right triangle whose hypotenuse is the diagonal of the cube. The height of the cube is the vertical side of the right triangle whose hypotenuse is the diagonal of the cube. Now determine the length of the diagonal of the cube. (diagonal of base)^2 + (height of cube)^2 = (diagonal of cube )^2 Diagonal of base = (s^2 + s^2 )^0.5….Height of cube = s Use Pythagorean Theorem (diagonal of cube )^2 = (diagonal of base)^2 + (height of cube)^2 (diagonal of base)^2 = [(s^2 + s^2 )^0.5]^2 = s^2 + s^2 height of cube)^2 = s^2 (diagonal of cube)^2 = (s^2 + s^2 + s^2) (diagonal of cube )^2 = (3 * s^2) diagonal of cube = (3 * s^2)^0.5 = 35 (3 * s^2)^0.5 = 35 Square both sides 3s^2 = 31^2 = 1225 s^2 = 408.33 s = 40833^0.5 s = 20.2 cm
How do you find the body diagonal of a cube if you already have the face diagonal?
First square the face diagonal Then multiply the result by 3 Next divide that by 2 And finally take the positive root to get the body diagonal
