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The longest diagonal of a 6 cm cube is: 10.39 cm

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Q: What is the longest diagonal in a 6cm cube?
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What is the surface area of cube whose longest diagonal is 6cm?

It is 72 sq cm.


What is the name of the longest diagonal of the cube?

The principal diagonal.


How do you find the edge of a cube if the measure of the diagonal is given?

The longest diagonal in a cube is equal to the length of the edge, multiplied by the square root of 3.


What is the volume of a cube that is 6cm on each edge?

The volume of a cube that is 6cm on each edge is: 216 cm3


Is the cube diagonal and plane diagonal of a cube the same?

No.


What is the length of the longest diagonal inside a cuboid of the lengths 6cm 10cm and 8cm?

It is sqrt(62 + 102 + 82) = sqrt(200) = 60.53 cm (approx).


What is the surface area of a 6 cm cube?

assuming you mean the cube has 6cm sides....each face of the cube has an area of 6cm x 6cm = 36cm2A cube has 6 faces so the total surface area is 6 x 36 = 216cm2


What is the volume of a cube with a side length of 6cm?

The volume of the cube is 216 cm3


How can I figure the dimensions of a perfect cube if the hypotenuse through the center of the cube is 35cm?

Somehow I messed up andused 31 instead of 35 That is why you are receiving an improvement Do a Google search for Diagonal of a cube Find this website. mathcentral.uregina.ca/QQ/database/QQ.09.04/brett1.HTML - Draw a cube You will see how to find the diagonal of a cube. You use Pythagorean Theorem Draw a cube Label each side as s Draw the diagonal of the base of the cube Diagonal of base = (s^2 + s^2 )^0.5 Let the diagonal of the base be the horizontal side of the right triangle whose hypotenuse is the diagonal of the cube. The height of the cube is the vertical side of the right triangle whose hypotenuse is the diagonal of the cube. Now determine the length of the diagonal of the cube. (diagonal of base)^2 + (height of cube)^2 = (diagonal of cube )^2 Diagonal of base = (s^2 + s^2 )^0.5….Height of cube = s Use Pythagorean Theorem (diagonal of cube )^2 = (diagonal of base)^2 + (height of cube)^2 (diagonal of base)^2 = [(s^2 + s^2 )^0.5]^2 = s^2 + s^2 height of cube)^2 = s^2 (diagonal of cube)^2 = (s^2 + s^2 + s^2) (diagonal of cube )^2 = (3 * s^2) diagonal of cube = (3 * s^2)^0.5 = 35 (3 * s^2)^0.5 = 35 Square both sides 3s^2 = 31^2 = 1225 s^2 = 408.33 s = 40833^0.5 s = 20.2 cm


What is the length in inches of a diagonal of a 20 foot cube?

12 inches = 1 foot. 240 inches = 20 feet. Use Pythagoras' theorem to find the diagonal of one of the faces of the cube. 2402+2402 = 115200. The square root of 115200 is 339.411255 Therefore the diagonal of the cube is 339.411255 inches or 339 inches correct to three significant figures Incidentally, by using the above answer and Pythagoras' theorem we can also work out the length of the longest internal diagonal within the cube which works out exactly as 340 inches.


If a diagonal of a cube is known how to find the volume of the cube?

If the diagonal is d thenV = [d/sqrt(3)]^3


What is the length of the longest diagonal in a 6 cm cube?

sqrt(62 + 62 + 62 ) = sqrt(36*3) = sqrt(108) = 10.39 cm