sqrt(62 + 62 + 62 ) = sqrt(36*3) = sqrt(108) = 10.39 cm
6cm.
6*6*6 = 216cm3
The area of the square is 18 cm2 The area of a square is: area = side2 By Pythagoras: side2 + side2 = diagonal2 ⇒ 2 side2 = diagonal2 ⇒ side2 = diagonal2 ÷ 2 ⇒ area = diagonal2 ÷ 2 diagonal = 6cm, so: area = (6 cm)2 ÷ 2 ⇒ area = 18 cm2
6cm
It is 72 sq cm.
The principal diagonal.
The longest diagonal in a cube is equal to the length of the edge, multiplied by the square root of 3.
The volume of a cube that is 6cm on each edge is: 216 cm3
No.
It is sqrt(62 + 102 + 82) = sqrt(200) = 60.53 cm (approx).
The volume of the cube is 216 cm3
Somehow I messed up andused 31 instead of 35 That is why you are receiving an improvement Do a Google search for Diagonal of a cube Find this website. mathcentral.uregina.ca/QQ/database/QQ.09.04/brett1.HTML - Draw a cube You will see how to find the diagonal of a cube. You use Pythagorean Theorem Draw a cube Label each side as s Draw the diagonal of the base of the cube Diagonal of base = (s^2 + s^2 )^0.5 Let the diagonal of the base be the horizontal side of the right triangle whose hypotenuse is the diagonal of the cube. The height of the cube is the vertical side of the right triangle whose hypotenuse is the diagonal of the cube. Now determine the length of the diagonal of the cube. (diagonal of base)^2 + (height of cube)^2 = (diagonal of cube )^2 Diagonal of base = (s^2 + s^2 )^0.5….Height of cube = s Use Pythagorean Theorem (diagonal of cube )^2 = (diagonal of base)^2 + (height of cube)^2 (diagonal of base)^2 = [(s^2 + s^2 )^0.5]^2 = s^2 + s^2 height of cube)^2 = s^2 (diagonal of cube)^2 = (s^2 + s^2 + s^2) (diagonal of cube )^2 = (3 * s^2) diagonal of cube = (3 * s^2)^0.5 = 35 (3 * s^2)^0.5 = 35 Square both sides 3s^2 = 31^2 = 1225 s^2 = 408.33 s = 40833^0.5 s = 20.2 cm
12 inches = 1 foot. 240 inches = 20 feet. Use Pythagoras' theorem to find the diagonal of one of the faces of the cube. 2402+2402 = 115200. The square root of 115200 is 339.411255 Therefore the diagonal of the cube is 339.411255 inches or 339 inches correct to three significant figures Incidentally, by using the above answer and Pythagoras' theorem we can also work out the length of the longest internal diagonal within the cube which works out exactly as 340 inches.
If the diagonal is d thenV = [d/sqrt(3)]^3
sqrt(62 + 62 + 62 ) = sqrt(36*3) = sqrt(108) = 10.39 cm
It is an unbelivable 6cm!