The edge length of a cube with a diagonal of 9 ft is: 5.196 feet.
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You can use pythagorean theorem twice to find the diagonal of a cube
If each cube side is of length s, then the diagonal of the BASE is from Pythagorean theorem sqrt ( s^2 + s^2) = sqrt (2) times s = 1.414s The height of the cube is s, so we use the theorem again using the base diagonal and height to get the cube diagonal: sqrt( (1.414s)^2 + s^2) = sqrt (3s^2) = sqrt(3) times s = 1.732s
find the cube root of 125(which is 5) is the length of one side do Pythagorean theorem to find the diagonal 5squared plus 5 squared=50 square root of 50=7.07106781 is diagonal
The longest diagonal of a 6 cm cube is: 10.39 cm
The longest diagonal in a cube is equal to the length of the edge, multiplied by the square root of 3.
It is 72 sq cm.
No.
12 inches = 1 foot. 240 inches = 20 feet. Use Pythagoras' theorem to find the diagonal of one of the faces of the cube. 2402+2402 = 115200. The square root of 115200 is 339.411255 Therefore the diagonal of the cube is 339.411255 inches or 339 inches correct to three significant figures Incidentally, by using the above answer and Pythagoras' theorem we can also work out the length of the longest internal diagonal within the cube which works out exactly as 340 inches.
Somehow I messed up andused 31 instead of 35 That is why you are receiving an improvement Do a Google search for Diagonal of a cube Find this website. mathcentral.uregina.ca/QQ/database/QQ.09.04/brett1.HTML - Draw a cube You will see how to find the diagonal of a cube. You use Pythagorean Theorem Draw a cube Label each side as s Draw the diagonal of the base of the cube Diagonal of base = (s^2 + s^2 )^0.5 Let the diagonal of the base be the horizontal side of the right triangle whose hypotenuse is the diagonal of the cube. The height of the cube is the vertical side of the right triangle whose hypotenuse is the diagonal of the cube. Now determine the length of the diagonal of the cube. (diagonal of base)^2 + (height of cube)^2 = (diagonal of cube )^2 Diagonal of base = (s^2 + s^2 )^0.5….Height of cube = s Use Pythagorean Theorem (diagonal of cube )^2 = (diagonal of base)^2 + (height of cube)^2 (diagonal of base)^2 = [(s^2 + s^2 )^0.5]^2 = s^2 + s^2 height of cube)^2 = s^2 (diagonal of cube)^2 = (s^2 + s^2 + s^2) (diagonal of cube )^2 = (3 * s^2) diagonal of cube = (3 * s^2)^0.5 = 35 (3 * s^2)^0.5 = 35 Square both sides 3s^2 = 31^2 = 1225 s^2 = 408.33 s = 40833^0.5 s = 20.2 cm
If the diagonal is d thenV = [d/sqrt(3)]^3
sqrt(62 + 62 + 62 ) = sqrt(36*3) = sqrt(108) = 10.39 cm
The edge length of a cube with a diagonal of 9 ft is: 5.196 feet.
Use Pythagoras' theorem to find the length of the outer diagonal and then use this as the base for the inner diagonal (the longest length of the cube) 82+82 = 128 and the square root of this is 11.3137085 cm 11.31370852+82 = 192 and the square root of this is 13.85640646 cm The longest pencil is 13.85640646 or just under 14 cm
The diagonal will be 8.66 cm
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