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You need more information than this. What type of triangle (right angle or not), and you need to know atleast one side's length (or you can choose the size of one or two sides, and determine the rest.) E.g., for right angled triangle, area = 1/2 base x height. If you want base and height same size, you can determine this from this formula using area (known)
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What condition for a triangle produce triangles that have the same area?
If another triangle has the same three sides, that is, sides of the same length, it will have the same area. Note that this is a sufficient, but not a necessary, condition, since you can also have triangles of a different shape that have the same area.
How do you find perimeter and area of triangles?
Perimeter . . . add up the lengths of all three sides. Area . . . multiply (half the length of the base) by (the height).
How do you work out the area a regular hexagon?
If all the vertices of the regular hexagon are joined to the centre of the hexagon, 6 equilateral triangles are created: the area of the hexagon is 6 times the area of one of these triangles. If the length of the side of the hexagon is m, then the length of each of the sides of these triangles is also m. Using Pythagoras the height of these triangles can be found to be m x sqrt(3)/2. Thus the area of the hexagon = 6 x area triangle = 6 x (m x m x sqrt(3)/2) / 2 = (3/2) sqrt(3) m2 ~= 2.6 x square of length_of_side
Do 2 triangles with 2 equal sides have the same area?
Only if the two triangles are congruent will they have equal areas. A third fact is required to determine they are congruent (and thus have the same area): 1) The third sides are equal; 2) The angles enclosed between the sides are equal; or 3) The same one of the sides is the hypotenuse of the triangles, which are right angled triangles.
How does the net of a triangular prism help you find the surface area of the prism?
A triangular prism has 5 sides. Three are rectangles and two are triangles. If you fold the net out flat you can get the dimensions and find the surface area. Each rectangle is length by width. And the triangles should be congruent and remember are length times height divided by two.
What condition for a triangle produce triangles that have the same area?
If another triangle has the same three sides, that is, sides of the same length, it will have the same area. Note that this is a sufficient, but not a necessary, condition, since you can also have triangles of a different shape that have the same area.
How do you find the area of the shaded region in a rectangle?
You will need to divide the shaded area into smaller parts, such as triangles or rectangles, or find the length of sides of these polygons.
How do you find perimeter and area of triangles?
Perimeter . . . add up the lengths of all three sides. Area . . . multiply (half the length of the base) by (the height).
What is the area of the parallelogram Round to the nearest tenth of a meter?
Can't do it Monique. The area depends on the size and angles of the sides; you've given us none of these. But I can give you an equation to plug in those numbers if you have them to come up with the area. generally area = A = area of the box + area of the triangles = L*l sin(alpha) + l^2 sin(alpha)cos(alpha); where the length of the parallel sides is L + l cos(alpha) and l is the diagonal length of each slanted side (of a triangle). Alpha is the angle of the slanted sides relative to a parallel side. NOTE: the "box" is the rectangle made up of the two parallel sides minus the lengths of the two triangles. Also note the two triangles fit together to form a smaller box; so we multiply its sides for the area the triangles contribute.
How do you work out the area a regular hexagon?
If all the vertices of the regular hexagon are joined to the centre of the hexagon, 6 equilateral triangles are created: the area of the hexagon is 6 times the area of one of these triangles. If the length of the side of the hexagon is m, then the length of each of the sides of these triangles is also m. Using Pythagoras the height of these triangles can be found to be m x sqrt(3)/2. Thus the area of the hexagon = 6 x area triangle = 6 x (m x m x sqrt(3)/2) / 2 = (3/2) sqrt(3) m2 ~= 2.6 x square of length_of_side
What is the TOTAL surface area of an icosahedron?
An icosahedron is a body enclosed by 20 triangles. The total surface area is the sum of the areas of the individual triangles. In the case of a regular icosahedron, it is of course 20 times the surface area of any of the triangles - i.e., 5 times the square root of 3 times a2, where "a" is the length of one of the sides.
Do 2 triangles with 2 equal sides have the same area?
Only if the two triangles are congruent will they have equal areas. A third fact is required to determine they are congruent (and thus have the same area): 1) The third sides are equal; 2) The angles enclosed between the sides are equal; or 3) The same one of the sides is the hypotenuse of the triangles, which are right angled triangles.
How does the net of a triangular prism help you find the surface area of the prism?
A triangular prism has 5 sides. Three are rectangles and two are triangles. If you fold the net out flat you can get the dimensions and find the surface area. Each rectangle is length by width. And the triangles should be congruent and remember are length times height divided by two.
How do you fine the area of triangles?
height x length / 2
How do you find the diagonals of a square when you have the area of the square?
A diagonal bisecting a square creates two identical right triangles. The diagonal is the hypotenuse of a right triangles, so its length is the square root of the sums of the squares on the opposite two sides.
What is the area of equilateral triangles with sides of 10 inches and heigth of 7 inches?
Using Pythagoras' theorem it is impossible for an equilateral triangle with equal sides of 10 inches to have a height of 7 inches.
What is the length of one side of a triangle if its area is 64 ft squared?
The area doesn't tell you the shape of the triangle or the lengths of its sides.There are an infinite number of different triangles, all with sides of differentlengths, that all have 64 ft2 of area.
