You need more information than this. What type of triangle (right angle or not), and you need to know atleast one side's length (or you can choose the size of one or two sides, and determine the rest.) E.g., for right angled triangle, area = 1/2 base x height. If you want base and height same size, you can determine this from this formula using area (known)
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If another triangle has the same three sides, that is, sides of the same length, it will have the same area. Note that this is a sufficient, but not a necessary, condition, since you can also have triangles of a different shape that have the same area.
Perimeter . . . add up the lengths of all three sides. Area . . . multiply (half the length of the base) by (the height).
If all the vertices of the regular hexagon are joined to the centre of the hexagon, 6 equilateral triangles are created: the area of the hexagon is 6 times the area of one of these triangles. If the length of the side of the hexagon is m, then the length of each of the sides of these triangles is also m. Using Pythagoras the height of these triangles can be found to be m x sqrt(3)/2. Thus the area of the hexagon = 6 x area triangle = 6 x (m x m x sqrt(3)/2) / 2 = (3/2) sqrt(3) m2 ~= 2.6 x square of length_of_side
Only if the two triangles are congruent will they have equal areas. A third fact is required to determine they are congruent (and thus have the same area): 1) The third sides are equal; 2) The angles enclosed between the sides are equal; or 3) The same one of the sides is the hypotenuse of the triangles, which are right angled triangles.
A triangular prism has 5 sides. Three are rectangles and two are triangles. If you fold the net out flat you can get the dimensions and find the surface area. Each rectangle is length by width. And the triangles should be congruent and remember are length times height divided by two.