Draw a tangent to the curve at the point where you need the gradient and find the gradient of the line by using gradient = up divided by across
graph it
By the substitution method By the elimination method By plotting them on a graph
To find the inflection points on a graph, you need to take the second derivative. Then, set that equal to zero to find the x value(s) of the inflection point(s).
A pair of numbers are usually (x,y) if u want to determine a point on a graph. Find the value for both x and y and then plot them on a graph
3s=2t can also be written as 3y=2x or 3x=2y. Either way, it is linear. To find out if it is linear, simply graph it. If you can draw a completely vertical line through any point of the graph without intersecting more than one point of the graph, then it is linear. This equation (3s=2t), it is linear.
Follow the graph's positive slope (across the first quadrant) until the graph is no longer linear. The yield strength is determined to be the last point (with concern given to the stress value) on the linear section. After this point the graph is irregular because the material has failed to a point of no return and can no longer handle the load (stress).
To find acceleration from a speed-time graph, you need to calculate the slope of the speed-time graph. The slope at any point on the speed-time graph represents the acceleration at that specific time. If the speed-time graph is linear, then the acceleration will be constant. If the speed-time graph is curved, you can find the acceleration by calculating the slope of the tangent line at a specific point.
A linear function is called "linear" because it represents a straight line. To graph a linear function, find two points that satisify that function, plot them, and then draw a straight line between them.
You would want to find were it starts on the graph so that would be your starting point on the table and then you would have to go up by rise over run for x and then you are mostliky done
Draw a tangent to the curve at the point where you need the gradient and find the gradient of the line by using gradient = up divided by across
To find the y-intercept from a graph - look at where the graph of the line intersects the y-axis. The point at where the graph of the line crosses the y-axis will be the y-intercept with the coordinates of (0,y) The point at which the line cuts the y – axis is called as y – intercept.You can locate the point by seeing the graph.Note:If you are given a linear equation say ax + by + c = 0Now if we plug x = 0 in the given equation we will get the y – intercept.y = -c/bIf the given equation is of the form y = mx + bb is the y – intercept of the line. Source: www.icoachmath.com
Two ways: Way 1: Find two points on the line, graph, and extend line. Way 2: Put the equation in slope-intercept form, plot the constant, use the slope to find the next point(s). Extend the line.
graph it
Find the slope of the tangent to the graph at the point of interest.
Here is a simple way to graph a linear equation. A linear equation is one that has a y term (a number times y), an x term and a constant (but no squares or cubes or square roots etc.): Let x = 0 and use the equation to find y. This gives you one point on the graph: (0, -3) Let y = 0 and use the equation to find x. This gives you another point on the graph (3, 0) Plot these two points, join them with a line and extend in both directions. However, this method gives only one point if the equation is of the form y = ax where a is some non-zero constant; and that point is (0,0) In that case, use (1,a) as the second point.
you have to look at the graph. find where the line crosses the x and y axis' and there is your solutions.