if the answer, for example, was "FIND THE NTH TERM OF THESE NUMBERS" and they listed:
1, 1/4, 1/9, 1/16, 1/25...
then this is how I personally would go about it.
okay, so the first term is 1. write them all down like this:
1. 1
2. 1/4
3. 1/9
4. 1/16
5. 1/25
(it makes it easier to see which term is which)
as they are all over ONE, you can ignore the top number and focus on the bottom one --> and remember that 1 = 1/1.
square the N number; what do you get?
1*1 = 1
2*2 = 4
3*3 = 9
4*4 = 16
5*5 = 25
so we now have n^2 (N squared), but they aren't a fraction. *sad face*
this is where we take the expression N squared and we put a 1 over it (since all of the terms are over 1:
1/n^2 (one over N squared)
if the answers were all over 2, put -- 2 over [the expression to solve the denominator (bottom number)] -- and so on.
hope this helped :)
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my nth term maths is very tuff because its syallabus is changed
You don't.
The nth term is 7n-3 and so the next term will be 39
The given sequence is decreasing by 2 each time, so the pattern is -2. To find the nth term, we can use the formula for the nth term of an arithmetic sequence: (a_n = a_1 + (n-1)d), where (a_n) is the nth term, (a_1) is the first term, (n) is the term number, and (d) is the common difference. In this case, the first term (a_1 = 11), the common difference (d = -2), and we want to find the nth term. So, the nth term formula becomes (a_n = 11 + (n-1)(-2) = 13 - 2n).
It is not possible to determine an nth term from a single number.