Multiply the possible outcomes of the events in the disjoint events
When two events are disjoint (or mutually exclusive), it means that they cannot occur at the same time; if one event occurs, the other cannot. Consequently, disjoint events cannot be independent, because the occurrence of one event affects the probability of the other event occurring. In fact, for disjoint events, the probability of both events happening simultaneously is zero, which contradicts the definition of independence where the occurrence of one event does not influence the other. Therefore, disjoint events are not independent.
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Two events are disjoint if they cannot occur together. In set terms, their intersection is a null set.
No.
It depends on whether or not the events are independent.
In probability theory, disjoint events are two (or more) events where more than one cannot occur in the same trial. It is possible that none of them occur in a particular trial.
If two events are disjoint, they cannot occur at the same time. For example, if you flip a coin, you cannot get heads AND tails. Since A and B are disjoint, P(A and B) = 0 If A and B were independent, then P(A and B) = 0.4*0.5=0.2. For example, the chances you throw a dice and it lands on 1 AND the chances you flip a coin and it land on heads. These events are independent...the outcome of one event does not affect the outcome of the other.
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If they're disjoint events: P(A and B) = P(A) + P(B) Generally: P(A and B) = P(A) + P(B) - P(A|B)
Two events are disjoint if they cannot occur together. In set terms, their intersection is a null set.
No.
no
The answer depends on whether or not the events are independent.
It depends on whether or not the events are independent.
you find the probability
Complements or complementary events
Aces and 9s are disjoint events, so the probability of either is the sum of the probabilities of each. P(A or 9) = P(A) + P(9) = 1/13 + 1/13 = 2/13