answersLogoWhite

0


Best Answer

First, we'll rearrange the expression in the standard format of ax2 + bx + c = 0:

3x2 - 5x = 2

3x2 - 5x - 2 = 0

Now we need to find two numbers whose sum is negative five (coefficient of the second term), and whose product is negative 6 (product of the coefficients of the first and last terms). Those two numbers in this case would be negative six and one. We'll break the middle term down into two terms using those coefficients:

3x2 - 6x + x - 2 = 0

Now we factor out a common multiple between our first two and last two terms:

3x(x - 2) + 1(x - 2) = 0

And we can group common terms:

(3x + 1)(x - 2) = 0

Giving us the fully factored expression on the left.

User Avatar

Wiki User

12y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How do you find the roots 3x2-5x equals 2?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Related questions

Find the sum of the roots x2 plus 3x equals -2?

-3/2


If the sum of the roots of x to the power of 3 minus x to the power of 2 minus 2x plus 2 equals 0 is zero find all the roots?

1 and the positive and negative square roots of 2


What is the product of the roots of the equation 2xsquare-x-2 equals 0?

The product of the roots of the equation 2x2 -x -2 = 2 is 2x2 -x -2 = 2.


What is 4 square roots of x equals 8 plus 2 square roots of x?

x=16


How do you find the value of 'a' in simplest radical form in the equation 'a square roots of 2 equals 18'?

You're going to want to multiply the square root of 2 by itself to get rid of it. Then you're left with x times 2 equals 18. a = 9√2


Find 'a' when xsquared plus ax minus 15 equals 0 has two integer roots?

(x + 1)(x - 15) gives roots of -1 and 15, and a = 14; (x + 5)(x - 3) gives roots of -5 and 3, and a = 2.


What is the nature of the roots of the equation 2xsquared-6x plus 2 equals 0?

It has roots x = 2.618 and x = 0.38197


Which are the roots of X3minus3x2minus9xminus5 equals 0?

(x - 5)(x + 1)2


What is the number and type of roots of the equation x2-4x-32 equals 0?

There are 2 roots to the equation x2-4x-32 equals 0; factored it is (x-8)(x+4); therefore the roots are 8 & -4.


Roots of the equation x 2 plus 5x plus 7 equals 0 will be?

There are no real root. The complex roots are: [-5 +/- sqrt(-3)] / 2


How many roots does y equals x2-4x plus 4 have?

y = x2-4x+4 Since the highest degree term is 2, it must have 2 roots


What is the value of m in 25x2-20x plus m equals 0 so that the two roots are equal?

4 and the two equal roots are 2/5 and 2/5