There are 2 roots to the equation x2-4x-32 equals 0; factored it is (x-8)(x+4); therefore the roots are 8 & -4.
The product of the roots of the equation 2x2 -x -2 = 2 is 2x2 -x -2 = 2.
It is a quadratic equation with one unknown variable, x which has no real roots.
2x2 - 5x - 3 = 0 A quadratic equation expressed in the form ax2 + bx + c = 0 has two real and distinct roots when b2 - 4ac is positive. Using the figures from the supplied equation then b2 - 4ac = 52 - (4 x 2 x -3) = 25 + 24 = 49. Therefore there are TWO real and distinct roots.
If p, q, r, ... are the roots of the equations, then (x-p), (x-q), (x-r), etc are the factors (and conversely).
Use the quadratic formula, with a = 1, b = -3, c = 2.
-4,3 are the roots of this equation, so for the values for which the sum of roots is 1 & product is -12
The discriminant is -27 and so there are no real roots.
They are called the solutions or roots of the equations.
Such an equation has a total of six roots; the number of real roots must needs be even. Thus, depending on the specific equation, the number of real roots may be zero, two, four, or six.
The product of the roots of the equation 2x2 -x -2 = 2 is 2x2 -x -2 = 2.
It has roots x = 2.618 and x = 0.38197
This quadratic equation has no real roots because its discriminant is less than zero.
The roots are: x = -5 and x = -9
These are the real ROOTS of the quadratic equation when it equals zero. Example : x2- 7x + 10 = 0 can be written as (x - 5)(x - 2) = 0 Then x = 5 and x = 2 are the roots of this equation.
The roots of the equation are [5 +/- sqrt(11)]/2 = 4.158 and 0.842
It has no real roots.
normally an equation with the x value squared there would be two roots. the two roots are positive 1 and postitive 1. since they are they same number there is actually only one root.