You use the point-slope formula. m= (x2-x1)/(y2-y1). So say the points are (5,2) and (9,4) you subtract 9-2, and 4-5 and divide that, getting -7 (which by the way is a huge slope).
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According to the question, you HAVE the point!
a parabola doesn't have one slope, the slope is constantly changing as you move accross the graph. however, it is possible to find a slope to a line tangent to a point on a parabola. to do this, take the derivative of the equation for the given parabola. then, take the X,Y coordinate and plug in the x value for the point. So, if the graph of of the equation was given by y=x^2, the derivative would be dy/dx=2x. you would then take a point, e.x. (2,4) and plug in the x value, 2, into dy/dx=2x, yielding a slope of 4 for the line tangent to that point.
If the line is a straight line, meaning 180degrees, it can only have one slope. If it is a function (f(x)= or y=) then the line may have more than one, one, or an undefined slope. Find the first differential of the function and plug in your given x value to find the slope at any given point.
Assuming the point is (3, -6) and the slope 1, the equation is x - y - 9 = 0
You need either a point and the slope of the line or two points. Then you use the point slope form of the line or the slope intercept form to write the lines.A given point has an infinite number of lines going through it, that is why you need more information.