The straight line equation is: y = mx+c whereas m is the slope and c is the y intercept
If the slope m is given at a point (xo, yo) of a line, then the equation of the line is given by: y - yo = m(x - xo)
The answer will depend on the context. If the curve in question is a differentiable function then the gradient of the tangent is given by the derivative of the function. The gradient of the tangent at a given point can be evaluated by substituting the coordinate of the point and the equation of the tangent, though that point, is then given by the point-slope equation.
That will depend on the value of the slope which has not been given.
The given expression is not an equation because it has no equality sign
If the slope is 2/3 and the coordinate is (2, -1) then the straight line equation is 3y=2x-7
Given point: (6, 7) Equation: 3x+y = 8 Parallel equation: 3x+y = 25
The straight line equation is: y = mx+c whereas m is the slope and c is the y intercept
If the slope m is given at a point (xo, yo) of a line, then the equation of the line is given by: y - yo = m(x - xo)
Substitute the x coordinate into the equation for x and calculate y. If the formla gives the same y value as the coordinates, the point is on the line. If it is diffent, it is not on the line.
Substitute the coordinates of the point into the equation of the line. If the equation is still valid then the point is on the line; if not then it is not.
The answer will depend on the context. If the curve in question is a differentiable function then the gradient of the tangent is given by the derivative of the function. The gradient of the tangent at a given point can be evaluated by substituting the coordinate of the point and the equation of the tangent, though that point, is then given by the point-slope equation.
Without an equality sign the given expression can't be considered to be a straight line equation. But lines that are parallel to each other have the same slope and different y intercepts.
That will depend on the value of the slope which has not been given.
The equation is x = -7.
If you know the slope of the line that your equation is perpendicular too, you find the negative reciprocal of it and use it as the slope for the line. (negative reciprocal = flip the slope over and change its sign. Ex: a slope of 2 has a negative reciprocal of -1/2. ) Then you use the given point, and put your equation in point-slope form. The general equation for point slope form is Y-y1=m(x-x1) The y1 is the y coordinate of the given point. X1 is the x coordinate of the given point. M is the slope that you found earlier. You now have your equation. If you are asked to put it in slope intercept form, simply distribute the numbers and solve the equation for y.
Use point-slope formula