If the true value is t and the calculated or measured value is v then absolute error = |v - t|, the absolute value of (v - t).If v >= t then the absolute value is v - tif v
V = 4 + 4t Where V=value, and t = term number, where
That depends on the value of v.
That depends what the value of v is.
That depends what the value of v is.
The effective value of an AC = AC/√2. Example: the effective value of 8.5 V AC is 6.01 V, because 8.5/√2=6.01 Hope that helped :)
If the true value is t and the calculated or measured value is v then absolute error = |v - t|, the absolute value of (v - t).If v >= t then the absolute value is v - tif v
You need t to find the value.
V = 4 + 4t Where V=value, and t = term number, where
It is expressing a change in the value of something as a percentage of its original value. So, if the original value (V) changes to the new value (W) then the change is W - V. Then, the relative change is (W - V)/V and the percentage change is 100*(W - V)/V = 100*(W/V - 1)
That depends on the value of v.
the value of top in a stack is the value of the last recently pushed element.It could be imlpemented as:VALUE top (STACK s){VALUE v;v = POP (s);PUSH (s, v);return v;}
first need to find the voltage value to calculate the Power Dissipation. Because P= I*V Here V = IR in given value I = 30 m A = 0.03 A R= 5 K Ohm = 5000 V= 0.03*5000=150 V= 150 V Power dissipation p= 150*0.03=4.5 Watt
As a Roman numeral: V = 5
That depends what the value of v is.
Some are worth a lot and some aren't. In order to find out it's value ask another question but this time include the date.
That depends what the value of v is.