That depends on the value of v.
Replace you with u, typo sorry.
It's 1/2 squared times V divided by M V( velocity) M(matter)
All that can be said, based on the available information is: t + v2
There are 207.88556 cubic inches in the cylinder. To find the volume, you must multiply the area by the depth. To find the area, you multiply the radius-squared by pi (3.1416). The Area: A = pi x R-squared A = 3.1416 x 2.75 squared A = 3.1416 x 7.5625 A = 23.75835 The Volume: V = Area x Depth V = 23.75835 x 8.75 V = 207.88556
Seconds are squared in physics when calculating quantities that involve acceleration, such as in the formula for acceleration ( a = \frac{\Delta v}{\Delta t} ). Here, velocity (( v )) is measured in meters per second (m/s), and when you take the change in velocity over a change in time (seconds), the time component is squared to reflect the rate of change of velocity per unit of time. This results in units of meters per second squared (m/s²) for acceleration, indicating how much velocity changes per second.
Replace you with u, typo sorry.
Velocity squared is the velocity of an object multiplied by itself. It represents the kinetic energy of the object. Mathematically, it can be expressed as v^2, where v is the velocity of the object.
v2+36v+99 = (v+3)(v+33) when factored
v=3.14(r){squared}(h) The formula is pi x radius (squared) x the height.
Okay. Resistance by ohms law is given by R = V/I But Power P = V * I Dividing R/P = 1/ I 2 Or R = P / I squared For a constant power, resistance is inversely proportional to I squared and not simply proportional to.
Divide all terms by 4 and it then factors as: (v+4)(v-12)
Formula for the volume of a cylinder.
v = 3.14 times radius squared times height
It's 1/2 squared times V divided by M V( velocity) M(matter)
Using the equation for kenetic energy [KE=1/2*(X kg)*(V m/s)squared], KE will be reduced by V[squared]*(1/2), or 4x.
Rearranging: v² = u² + 2as → u² + 2as = v² ________________ writing equation the other way round to get u² on the left → u² = v² - 2as _________________ subtracting 2as from both sides → u = ±√(v² - 2as) ______________ taking the square root of both sides
change in velocity (v) = acceleration (a) x time (t); distance s = 1/2 a times t squared; solve for time and substitute; find a = v squared /(2s)