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X + (X + 1) + (X + 2) = - 12

3X + 3 = - 12

3X = - 15

X = - 5

------------

- 5 + ( - 5 + 1) + (- 5 + 2) = - 12

- 5 + ( - 4) + ( - 3) = -12

- 12 = -12

----------------so,

( - 3, - 4, - 5 ) are the three consecutive integers

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Q: How do you find three consecutive integers that have a sum of -12?
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