just to find the answer. like if it has an x in it then figure out what the x is
l x w x h
First the formula is g(x)=ax2+bx+c First find where the parabola cuts the x axis Then find the equation of the axis of symmetry Then
You would set the equation equal to 0 and then solve for x. You may get one or several answers for x, x being the number(s) that make the equation equal 0.
X = 0.13 x 50
To find the x-intercept you need to set y=0 in your equation. To find the y-intercept you need to set x=0 in your equation.
At the x-intercept on the graph of the equation, y=0. Take the equation, set 'y' equal to zero, and solve the equation for 'x'. The number you get is the x-intercept.
just to find the answer. like if it has an x in it then figure out what the x is
l x w x h
The question is suppose to read: Find the equation of the line tangent to y=(x²+3x)²(2x-2)³, when x=8
x is a variable. You do not have to know what its value is. In that equation you have to find the value of x, so if you already know what x stands for then you know the answer
For an equation of the form ax² + bx + c = 0 you can find the values of x that will satisfy the equation using the quadratic equation: x = [-b ± √(b² - 4ac)]/2a
x=100
An abstract equation is an equation where it is impossible, with the information given, to find the numeric values of the variables. For example 2X=4Y can be reduced to X=2Y or Y=X/2 or 2=X/Y but you cannot find the numeric values of X or Y.
Solve f(x) =0 or y = 0 (depending on how the equation is given).
First the formula is g(x)=ax2+bx+c First find where the parabola cuts the x axis Then find the equation of the axis of symmetry Then
You would set the equation equal to 0 and then solve for x. You may get one or several answers for x, x being the number(s) that make the equation equal 0.