For simple functions, f(x), you set f(x) = 0 and solve that.
For example, to find the 0 of 3x + 7
you set 3x - 7 = 0
so that 3x = 7 or x = 7/3. That is the 0 of the function.
However, there are plenty of functions where this method will fail because the function cannot be solved algebraically.
Linear and quadratic functions are easy; cubics are possible but tedious. Bur what about something like
6x2 + ln(x) = 7sin(x) where x is measured in radians ?
You then go for numerical solutions. This entails finding one approximate solution. Use that solution to find a better one and then use that one to find a still better one and so on. Hopefully (though not always) the iteration will converge to a root. One of the better known methods for this is the Newton-Raphson method.
These methods work for functions that are continuous and differentiable, but many functions are not. And then you go into some serious mathematics and, in order to explain that, I need to know a lot more about your mathematical knowledge.
false!
no a plynomial can not have more zeros than the highest (degree) number of the function at leas that is what i was taught. double check the math.
For an algebraic function in one variable, as many as the highest power of the variable.
Assuming it is a function of "x", those are two different names for the same thing.
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You cannot. The function f(x) = x2 + 1 has no real zeros. But it does have a minimum.
The zeros of a quadratic function, if they exist, are the values of the variable at which the graph crosses the horizontal axis.
In general, there is no simple method.
by synthetic division and quadratic equation
the zeros of a function is/are the values of the variables in the function that makes/make the function zero. for example: In f(x) = x2 -7x + 10, the zeros of the function are 2 and 5 because these will make the function zero.
The zeros of a function are the values of the independent variable where the dependent variable has value of zero. In a typical representation where y = f(x), the zeroes are the points x where y is 0.
The integral zeros of a function are integers for which the value of the function is zero, or where the graph of the function crosses the horizontal axis.
zeros makes a matrix of the specified dimension, filled with zeros.
You could try setting the function equal to zero, and finding all the solutions of the equation. Just a suggestion.
false!
Find All Possible Roots/Zeros Using the Rational Roots Test f(x)=x^4-81 ... If a polynomial function has integer coefficients, then every rational zero will ...
take out zeros