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The function ( f(x) = x^2 - 6x + 8 ) is a polynomial function because it is a quadratic expression. To find the zeros, we can factor it as ( (x - 2)(x - 4) ), which gives us the zeros ( x = 2 ) and ( x = 4 ). Thus, the zeros of the function are 2 and 4.

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State whether the following is a polynomial function give the zeros both real and imaginary of the function if they exist g x x 2-3x-4 x 2 plus 1?

The function ( g(x) = \frac{x^2 - 3x - 4}{x^2 + 1} ) is not a polynomial function because it is a rational function (the ratio of two polynomials). To find the zeros, we set the numerator equal to zero: ( x^2 - 3x - 4 = 0 ). The zeros can be found using the quadratic formula: ( x = \frac{3 \pm \sqrt{(3)^2 - 4(1)(-4)}}{2(1)} ), which simplifies to ( x = 4 ) and ( x = -1 ). The denominator ( x^2 + 1 = 0 ) gives imaginary zeros ( x = i ) and ( x = -i ).


What are the following functions state the vertex and what transformations on the parent function are needed to make the graph of the given function?

To determine the vertex and transformations of a given function, we first need the specific function itself. For example, if the function is in the form (f(x) = a(x-h)^2 + k), the vertex is ((h, k)). The transformations from the parent function (f(x) = x^2) would include a vertical stretch/compression by factor (a), a horizontal shift (h) units, and a vertical shift (k) units. If you provide the specific function, I can give a more detailed answer.


What does state whether your hypothesis was correct or not mean?

It means tell them how your hypothesis was right or not.


If the graph of quadratic function x has a minimum point and intersects the axis of x at 4 and m If the axis of symmetry of the graph is x equal to 5 state the value m and hence state the function x?

...i need the answer to that too...


State whether there can be an object with a constant acceleration but with zero velocity?

yes, if it has a constant acceleration of 0m/s2

Related Questions

What type of polynomial is formed by adding a second degree binomial to a fourth degree monomial. State the degree of this polynomial?

A fourth degree polynomial.


State whether the following is a polynomial function give the zeros both real and imaginary of the function if they exist g x x 2-3x-4 x 2 plus 1?

The function ( g(x) = \frac{x^2 - 3x - 4}{x^2 + 1} ) is not a polynomial function because it is a rational function (the ratio of two polynomials). To find the zeros, we set the numerator equal to zero: ( x^2 - 3x - 4 = 0 ). The zeros can be found using the quadratic formula: ( x = \frac{3 \pm \sqrt{(3)^2 - 4(1)(-4)}}{2(1)} ), which simplifies to ( x = 4 ) and ( x = -1 ). The denominator ( x^2 + 1 = 0 ) gives imaginary zeros ( x = i ) and ( x = -i ).


Which of the following is a function of state government but NOT of national government?

maintaining a public school system cooley


Which of the following is a function of state or local givernment but not of the national government?

maintaining a public school system.


Is the following function linear or nonlinear If linear, state the rate of change?

o function is given. However, if linear , then the rate of change is the same as the steepness of the graph line.


Is enthalpy a state function?

Yes it is state function


Is mass a state function?

No, mass is not a state function.


Is temperature a state function?

Yes, temperature is a state function.


State the function of breather on powerpack?

state the function of breathercpower pack


Is pressure a state function in thermodynamics?

No, pressure is not a state function in thermodynamics.


Is work a state function in thermodynamics?

No, work is not a state function in thermodynamics.


Wave function for time independent harmonic oscillator?

The wave function for a time-independent harmonic oscillator can be expressed in terms of Hermite polynomials and Gaussian functions. It takes the form of the product of a Gaussian function and a Hermite polynomial, and describes the probability amplitude for finding the oscillator in a particular state. The solutions to the Schrödinger equation for the harmonic oscillator exhibit quantized energy levels, known as energy eigenstates.