The function ( f(x) = x^2 - 6x + 8 ) is a polynomial function because it is a quadratic expression. To find the zeros, we can factor it as ( (x - 2)(x - 4) ), which gives us the zeros ( x = 2 ) and ( x = 4 ). Thus, the zeros of the function are 2 and 4.
The function ( g(x) = \frac{x^2 - 3x - 4}{x^2 + 1} ) is not a polynomial function because it is a rational function (the ratio of two polynomials). To find the zeros, we set the numerator equal to zero: ( x^2 - 3x - 4 = 0 ). The zeros can be found using the quadratic formula: ( x = \frac{3 \pm \sqrt{(3)^2 - 4(1)(-4)}}{2(1)} ), which simplifies to ( x = 4 ) and ( x = -1 ). The denominator ( x^2 + 1 = 0 ) gives imaginary zeros ( x = i ) and ( x = -i ).
To determine the vertex and transformations of a given function, we first need the specific function itself. For example, if the function is in the form (f(x) = a(x-h)^2 + k), the vertex is ((h, k)). The transformations from the parent function (f(x) = x^2) would include a vertical stretch/compression by factor (a), a horizontal shift (h) units, and a vertical shift (k) units. If you provide the specific function, I can give a more detailed answer.
It means tell them how your hypothesis was right or not.
...i need the answer to that too...
yes, if it has a constant acceleration of 0m/s2
A fourth degree polynomial.
The function ( g(x) = \frac{x^2 - 3x - 4}{x^2 + 1} ) is not a polynomial function because it is a rational function (the ratio of two polynomials). To find the zeros, we set the numerator equal to zero: ( x^2 - 3x - 4 = 0 ). The zeros can be found using the quadratic formula: ( x = \frac{3 \pm \sqrt{(3)^2 - 4(1)(-4)}}{2(1)} ), which simplifies to ( x = 4 ) and ( x = -1 ). The denominator ( x^2 + 1 = 0 ) gives imaginary zeros ( x = i ) and ( x = -i ).
maintaining a public school system cooley
maintaining a public school system.
o function is given. However, if linear , then the rate of change is the same as the steepness of the graph line.
Yes it is state function
No, mass is not a state function.
Yes, temperature is a state function.
state the function of breathercpower pack
No, pressure is not a state function in thermodynamics.
No, work is not a state function in thermodynamics.
The wave function for a time-independent harmonic oscillator can be expressed in terms of Hermite polynomials and Gaussian functions. It takes the form of the product of a Gaussian function and a Hermite polynomial, and describes the probability amplitude for finding the oscillator in a particular state. The solutions to the Schrödinger equation for the harmonic oscillator exhibit quantized energy levels, known as energy eigenstates.