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What is the 35th term of the sequence in which a1 -10 and the common difference is 4?
an = 4n - 14 So a35 = 35*4 - 14 = 140 - 14 = 126
What is the missing number in the sequence 1 9 28 - 126 217?
65.......but there is a slight problem. The sequence appears to be a(n) = n3 + 1 apart from the first term which should be 2 as 13 + 1 = 2 1 23 + 1 = 9 33 + 1 = 28 43 + 1 = 65.....the missing number 53 + 1 = 126 63 + 1 = 217
What is the 35th term of a1 equals -10 and the common difference is 4?
To find the 35th term of an arithmetic sequence where the first term ( a_1 = -10 ) and the common difference ( d = 4 ), you can use the formula for the ( n )-th term: ( a_n = a_1 + (n-1) \cdot d ). Plugging in the values: [ a_{35} = -10 + (35-1) \cdot 4 = -10 + 34 \cdot 4 = -10 + 136 = 126. ] Thus, the 35th term is 126.
What is 72 over 126 in the lowest term?
4/7
What is 126 over 104 simplified?
63/52To reduce to lowest term:1. Get the GCF of 126 and 104126 = 2 * 3 * 3 * 7104 = 2...............* 2 * 2 * 13=================GCF =22. Divide 126 & 104 by their GCF.126 ÷ 2 = 63104 ÷ 2 = 52thus; lowest term is 63/52.
What is the 35th term of the sequence in which a1 -10 and the common difference is 4?
an = 4n - 14 So a35 = 35*4 - 14 = 140 - 14 = 126
What is the next in the number sequence 126?
Any number that you wish.
What is 126 over 2394in the lowest term and what number is the number divided by?
126/2394 = 1/19 by dividing by 126
What is the missing number in the sequence 1 9 28 - 126 217?
65.......but there is a slight problem. The sequence appears to be a(n) = n3 + 1 apart from the first term which should be 2 as 13 + 1 = 2 1 23 + 1 = 9 33 + 1 = 28 43 + 1 = 65.....the missing number 53 + 1 = 126 63 + 1 = 217
What is the 35th term of a1 equals -10 and the common difference is 4?
To find the 35th term of an arithmetic sequence where the first term ( a_1 = -10 ) and the common difference ( d = 4 ), you can use the formula for the ( n )-th term: ( a_n = a_1 + (n-1) \cdot d ). Plugging in the values: [ a_{35} = -10 + (35-1) \cdot 4 = -10 + 34 \cdot 4 = -10 + 136 = 126. ] Thus, the 35th term is 126.
What is 90 over 126 lowest term?
90/126 is 5/7 in its lowest terms
What is the first 5 terms of the geometric sequence a14r3?
They are 14, 42, 126, 378 and 1134.
What the sequence for 7 21 42 126 252 756?
1 3 6 18 36
What is 72 over 126 in the lowest term?
4/7
What is 126 over 104 simplified?
63/52To reduce to lowest term:1. Get the GCF of 126 and 104126 = 2 * 3 * 3 * 7104 = 2...............* 2 * 2 * 13=================GCF =22. Divide 126 & 104 by their GCF.126 ÷ 2 = 63104 ÷ 2 = 52thus; lowest term is 63/52.
What is the lowest term for the fraction 126 over 50?
63/25
What are the missing numbers in the sequence 123 126 129 N 133 136 N N 142 145 148?
151
